Kinematics Practice Questions
AP (Advanced Placement) · AP Physics 1 · 141 free MCQs with instant results and detailed explanations.
141
Total
51
Easy
69
Medium
21
Hard
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Sample Questions from Kinematics
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Q1
Easy
A car accelerates uniformly from rest at a rate of 2 m/s². How far does it travel in 5 seconds?
A.
25 m
B.
20 m
C.
30 m
D.
15 m
Show Answer & Explanation
Correct Answer: A
Using the formula for distance under uniform acceleration, d = ut + (1/2)at², where u = 0 m/s, a = 2 m/s², and t = 5 s, we get d = 0 + (1/2)(2)(5)² = 25 m.
Q2
Easy
A bicycle travels with a constant speed of 15 m/s for 10 seconds. How far does it cover during this time?
A.
150 m
B.
100 m
C.
200 m
D.
250 m
Show Answer & Explanation
Correct Answer: A
Distance can be calculated using the formula d = vt, where v = 15 m/s and t = 10 s. Therefore, d = 15 * 10 = 150 m.
Q3
Easy
A car accelerates from rest to a speed of 20 m/s in 10 seconds. What is the car's average acceleration?
A.
2 m/s²
B.
1 m/s²
C.
4 m/s²
D.
5 m/s²
Show Answer & Explanation
Correct Answer: A
Average acceleration is calculated by the change in velocity divided by the time taken. Here, the change in velocity is 20 m/s (final velocity) - 0 m/s (initial velocity) = 20 m/s. Thus, average acceleration = 20 m/s ÷ 10 s = 2 m/s².
Q4
Medium
A car accelerates uniformly from rest to a speed of 25 m/s over a distance of 200 m. What is the acceleration of the car?
A.
3.125 m/s²
B.
6.25 m/s²
C.
12.5 m/s²
D.
1.5 m/s²
Show Answer & Explanation
Correct Answer: A
Using the kinematic equation v² = u² + 2as, where v = 25 m/s, u = 0, and s = 200 m, we can solve for a: a = (v² - u²) / (2s) = (25² - 0²) / (2 * 200) = 3.125 m/s².
Q5
Medium
A car accelerates uniformly from rest to a speed of 20 m/s over a distance of 100 meters. What is the car's acceleration?
A.
4 m/s²
B.
8 m/s²
C.
2 m/s²
D.
10 m/s²
Show Answer & Explanation
Correct Answer: A
Using the formula v² = u² + 2as, where u = 0, v = 20 m/s, and s = 100 m, we rearrange to find a: a = (v² - u²)/(2s) = (20² - 0)/(2 * 100) = 4 m/s².
Q6
Medium
An object is thrown vertically upwards with an initial speed of 30 m/s. How high will it rise before it starts falling back to the ground? (Assume g = 9.8 m/s²)
A.
45.9 m
B.
46.1 m
C.
30.6 m
D.
61.2 m
Show Answer & Explanation
Correct Answer: B
Using the formula h = (v²)/(2g), where v = 30 m/s and g = 9.8 m/s², we find h = (30²)/(2 * 9.8) = 46.1 m.
Q7
Medium
If a ball is dropped from a height of 80 meters, how long will it take to reach the ground? (Assume g = 9.8 m/s²)
A.
4.04 s
B.
3.69 s
C.
3.00 s
D.
5.00 s
Show Answer & Explanation
Correct Answer: A
Using the formula t = √(2h/g), we substitute h = 80 m and g = 9.8 m/s². This gives t = √(2 * 80 / 9.8) = 4.04 s.
Q8
Hard
A car accelerates uniformly from rest to a speed of 25 m/s over a distance of 200 meters. What is the magnitude of the car's acceleration?
A.
1.56 m/s²
B.
3.12 m/s²
C.
6.25 m/s²
D.
12.50 m/s²
Show Answer & Explanation
Correct Answer: A
To find acceleration, we can use the kinematic equation: v² = u² + 2as. Here, v = 25 m/s, u = 0 m/s, and s = 200 m. Rearranging gives us a = (v² - u²) / (2s) = (25² - 0²) / (2 * 200) = 625 / 400 = 1.56 m/s².
Q9
Hard
A car accelerates uniformly from rest to a speed of 25 m/s over a distance of 200 meters. What is the magnitude of the car's acceleration?
A.
1.56 m/s²
B.
3.12 m/s²
C.
6.25 m/s²
D.
8.33 m/s²
Show Answer & Explanation
Correct Answer: A
Using the equation v² = u² + 2as, where v is the final velocity (25 m/s), u is the initial velocity (0 m/s), a is acceleration, and s is distance (200 m), we can solve for a. Rearranging gives a = (v² - u²) / (2s) = (25² - 0) / (2 * 200) = 625 / 400 = 1.56 m/s².
Q10
Hard
A projectile is launched at an angle of 30° with an initial velocity of 50 m/s. What is the maximum height reached by the projectile?
A.
63.25 m
B.
76.25 m
C.
85.00 m
D.
100.00 m
Show Answer & Explanation
Correct Answer: A
To find the maximum height, we use the formula h = (v₀² * sin²(θ)) / (2g). Here, v₀ = 50 m/s and θ = 30°, so sin(30°) = 0.5. Substituting gives h = (50² * (0.5)²) / (2 * 9.81) = (2500 * 0.25) / 19.62 = 63.25 m.
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Kinematics — AP (Advanced Placement) AP Physics 1 Practice Questions Online
This page contains 141 practice MCQs for the chapter Kinematics in AP (Advanced Placement) AP Physics 1. The questions are organized by difficulty — 51 easy, 69 medium, 21 hard — so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.