Electric Force Field and Potential Practice Questions
AP (Advanced Placement) · AP Physics 2 · 150 free MCQs with instant results and detailed explanations.
150
Total
47
Easy
75
Medium
28
Hard
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Sample Questions from Electric Force Field and Potential
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Q1
Easy
If a charge of 4 ฮผC is placed in an electric field of strength 300 N/C, what is the force experienced by the charge?
A.
1.2 N
B.
0.12 N
C.
120 N
D.
12 N
Show Answer & Explanation
Correct Answer: A
Using the formula F = qE, where F is the force, q is the charge (4 ฮผC = 4 x 10^-6 C), and E is the electric field (300 N/C), we calculate F = (4 x 10^-6 C)(300 N/C) = 1.2 N.
Q2
Easy
In a parallel plate capacitor, what happens to the electric potential difference if the distance between the plates is doubled while keeping the charge constant?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show Answer & Explanation
Correct Answer: B
The electric potential difference (V) across a capacitor is given by V = Q/C, where C is the capacitance. If the distance between plates is doubled, the capacitance halves (C โ 1/d), resulting in the potential difference halving, since charge is constant.
Q3
Easy
What is the electric field (E) generated by a point charge (Q) at a distance (r) from the charge?
A.
E = k * Q / r^2
B.
E = k * Q * r^2
C.
E = Q / (4 * ฯ * ฮตโ * r^2)
D.
E = k * r / Q
Show Answer & Explanation
Correct Answer: A
The electric field generated by a point charge is given by the formula E = k * Q / r^2, where k is Coulomb's constant. This formula shows that the electric field decreases with the square of the distance from the charge.
Q4
Medium
A point charge of +5 ยตC is placed in an electric field of strength 2000 N/C. What is the force experienced by the charge?
A.
10 N
B.
1 N
C.
100 N
D.
5 N
Show Answer & Explanation
Correct Answer: A
The force on a charge in an electric field is given by F = qE. Here, F = (5 ร 10^-6 C)(2000 N/C) = 10 N.
Q5
Medium
Two point charges, +3 ยตC and -3 ยตC, are placed 0.5 m apart. What is the magnitude of the electric potential energy of this system?
A.
-1.08 ร 10^-5 J
B.
1.08 ร 10^-5 J
C.
0 J
D.
-5.4 ร 10^-6 J
Show Answer & Explanation
Correct Answer: A
The electric potential energy U between two point charges is given by U = k(q1*q2)/r. Here, k = 8.99 ร 10^9 Nmยฒ/Cยฒ, q1 = 3 ร 10^-6 C, q2 = -3 ร 10^-6 C, and r = 0.5 m. U = (8.99 ร 10^9)(3 ร 10^-6)(-3 ร 10^-6)/0.5 = -1.08 ร 10^-5 J.
Q6
Medium
A capacitor with a capacitance of 10 ยตF is charged to a potential difference of 12 V. What is the energy stored in the capacitor?
A.
0.72 mJ
B.
0.06 mJ
C.
1.44 mJ
D.
0.12 mJ
Show Answer & Explanation
Correct Answer: A
The energy (U) stored in a capacitor is given by U = 1/2 CVยฒ. Here, C = 10 ร 10^-6 F and V = 12 V. Thus, U = 1/2 * (10 ร 10^-6) * (12)ยฒ = 0.72 mJ.
Q7
Medium
A uniform electric field of strength 500 N/C is directed horizontally. A charge of -2 ยตC is moved 0.4 m in the direction of the field. What is the work done on the charge?
A.
-0.4 J
B.
0.4 J
C.
1 J
D.
-1 J
Show Answer & Explanation
Correct Answer: A
Work done (W) on a charge in an electric field is given by W = qEd. Here, q = -2 ยตC = -2 ร 10^-6 C, E = 500 N/C, and d = 0.4 m. Thus, W = (-2 ร 10^-6)(500)(0.4) = -0.4 J.
Q8
Hard
A charge of +5 ฮผC is placed at the origin of a coordinate system. What is the electric potential (in volts) at a point 2 meters away from the charge in a vacuum? (Use k = 8.99 ร 10^9 N mยฒ/Cยฒ)
A.
2247.5
B.
179.5
C.
112.5
D.
8970
Show Answer & Explanation
Correct Answer: A
The electric potential (V) due to a point charge is given by the formula V = k * Q / r. Substituting the values: V = (8.99 ร 10^9 N mยฒ/Cยฒ) * (5 ร 10^-6 C) / (2 m) = 2247.5 V.
Q9
Hard
Two point charges, +3 ฮผC and -3 ฮผC, are placed 1 meter apart. What is the electric field at the midpoint between the charges?
A.
0 N/C
B.
4.5 ร 10^4 N/C towards -3 ฮผC
C.
4.5 ร 10^4 N/C towards +3 ฮผC
D.
9.0 ร 10^4 N/C towards +3 ฮผC
Show Answer & Explanation
Correct Answer: A
At the midpoint, the electric fields due to both charges will be equal in magnitude but opposite in direction, resulting in a net electric field of zero.
Q10
Hard
A point charge of +5 ฮผC is located at the origin of a coordinate system. Calculate the electric potential at a point located 0.3 m away from the charge. (Use k = 8.99 ร 10^9 Nยทmยฒ/Cยฒ)
A.
149.83 V
B.
89.97 V
C.
59.95 V
D.
29.97 V
Show Answer & Explanation
Correct Answer: A
The electric potential V at a distance r from a point charge Q is given by the formula V = k * Q / r. Here, V = (8.99 ร 10^9 Nยทmยฒ/Cยฒ) * (5 ร 10^-6 C) / 0.3 m = 149.83 V. Therefore, option A is correct.
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Electric Force Field and Potential โ AP (Advanced Placement) AP Physics 2 Practice Questions Online
This page contains 150 practice MCQs for the chapter Electric Force Field and Potential in AP (Advanced Placement) AP Physics 2. The questions are organized by difficulty โ 47 easy, 75 medium, 28 hard โ so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.