Fluids Practice Questions
AP (Advanced Placement) · AP Physics 2 · 152 free MCQs with instant results and detailed explanations.
152
Total
57
Easy
71
Medium
24
Hard
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Sample Questions from Fluids
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
What is the principle that states that an incompressible fluid in motion will have a constant flow rate throughout a streamline?
A.
Bernoulli's Principle
B.
Archimedes' Principle
C.
Pascal's Principle
D.
Continuity Equation
Show Answer & Explanation
Correct Answer: D
The Continuity Equation states that for an incompressible fluid, the product of the cross-sectional area and the flow velocity is constant along a streamline, which means the flow rate remains constant.
Q2
Easy
If a liquid is flowing through a horizontal pipe that narrows, what will happen to the velocity of the liquid in the narrower section?
A.
It will decrease.
B.
It will remain constant.
C.
It will increase.
D.
It will stop.
Show Answer & Explanation
Correct Answer: C
According to the Continuity Equation, when the cross-sectional area of a pipe decreases, the velocity of the liquid must increase to maintain a constant flow rate.
Q3
Easy
Which of the following factors does NOT affect the buoyant force acting on an object submerged in a fluid?
A.
Volume of the submerged part of the object
B.
Density of the fluid
C.
Mass of the object
D.
Acceleration due to gravity
Show Answer & Explanation
Correct Answer: C
The buoyant force is determined by the volume of fluid displaced and the density of the fluid, not by the mass of the object itself as given by Archimedes' Principle.
Q4
Medium
A 0.5 mยณ volume of an ideal gas is compressed isothermally at 300 K to a final pressure of 2.0 atm. What was the initial pressure of the gas? (Assume R = 0.0821 Lยทatm/(Kยทmol) and that n = 1 mol)
A.
1.0 atm
B.
1.5 atm
C.
2.0 atm
D.
0.5 atm
Show Answer & Explanation
Correct Answer: B
Using the ideal gas law, P1V1 = P2V2 and knowing it's isothermal, we can find P1. Since V1 = 0.5 mยณ = 500 L, and P2 = 2.0 atm, we can derive P1 = P2 * (V2/V1). Thus, P1 = 2.0 * (0.5/0.5) = 1.5 atm.
Q5
Medium
A block of wood with a density of 600 kg/mยณ is floating in water. What fraction of the block's volume is submerged? (Density of water is 1000 kg/mยณ)
A.
0.6
B.
0.4
C.
0.8
D.
0.5
Show Answer & Explanation
Correct Answer: A
For an object floating in a fluid, the fraction submerged is equal to the ratio of the density of the object to the density of the fluid. Here, 600 kg/mยณ (wood) / 1000 kg/mยณ (water) = 0.6.
Q6
Medium
If the atmospheric pressure is 101.3 kPa, what is the absolute pressure at a depth of 10 meters in a lake? (Assume density of water is 1000 kg/mยณ and g = 9.81 m/sยฒ)
A.
101.3 kPa
B.
201.3 kPa
C.
301.3 kPa
D.
401.3 kPa
Show Answer & Explanation
Correct Answer: B
Absolute pressure at depth is given by P = Pโ + ฯgh. Here, Pโ = 101.3 kPa, ฯ = 1000 kg/mยณ, g = 9.81 m/sยฒ, and h = 10 m. Thus, P = 101.3 + 1000 * 9.81 * 10 / 1000 = 201.3 kPa.
Q7
Medium
A cylindrical tank with a radius of 0.5 m is filled with water to a height of 2 m. Calculate the pressure at the bottom of the tank. (Use g = 9.81 m/sยฒ)
A.
9.81 kPa
B.
19.62 kPa
C.
39.24 kPa
D.
49.05 kPa
Show Answer & Explanation
Correct Answer: B
The pressure at a depth in a fluid is given by the formula P = ฯgh. For water (ฯ = 1000 kg/mยณ), at a depth of 2 m, P = 1000 * 9.81 * 2 = 19620 Pa = 19.62 kPa.
Q8
Hard
A fluid flows through a horizontal pipe with varying diameter; it narrows from diameter D1 to D2 (D2 < D1). If the velocity at the wider section (D1) is V1, what is the relationship between the pressures at the two sections, P1 and P2, according to Bernoulli's principle?
A.
P1 > P2
B.
P1 < P2
C.
P1 = P2
D.
P1 + 0.5ฯV1ยฒ = P2 + 0.5ฯV2ยฒ
Show Answer & Explanation
Correct Answer: A
According to Bernoulli's principle, as the fluid velocity increases when moving from a wider section to a narrower section, the pressure must decrease. Therefore, since V2 > V1, it follows that P1 must be greater than P2.
Q9
Hard
A horizontal pipe has a varying diameter. At point A, the diameter is 0.1 m and the velocity of the fluid is 2 m/s. At point B, the diameter is 0.05 m. What is the velocity of the fluid at point B?
A.
8 m/s
B.
4 m/s
C.
2 m/s
D.
16 m/s
Show Answer & Explanation
Correct Answer: A
According to the principle of continuity, the product of the cross-sectional area and velocity must remain constant. Thus, A1V1 = A2V2. With A1 = ฯ(0.1/2)ยฒ and A2 = ฯ(0.05/2)ยฒ, we find V2 = (A1/A2) * V1, which calculates to 8 m/s.
Q10
Hard
A container of height 2 meters is filled with water. Calculate the pressure exerted by the water at a depth of 1.5 meters. (Assume the density of water is 1000 kg/mยณ and g = 9.81 m/sยฒ)
A.
14715 Pa
B.
9810 Pa
C.
15000 Pa
D.
9800 Pa
Show Answer & Explanation
Correct Answer: A
Pressure at a depth in a fluid is given by the equation P = ฯgh. Here, ฯ = 1000 kg/mยณ, g = 9.81 m/sยฒ, and h = 1.5 m. Thus, P = 1000 * 9.81 * 1.5 = 14715 Pa.
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Fluids โ AP (Advanced Placement) AP Physics 2 Practice Questions Online
This page contains 152 practice MCQs for the chapter Fluids in AP (Advanced Placement) AP Physics 2. The questions are organized by difficulty โ 57 easy, 71 medium, 24 hard โ so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.