Linear Motion and Force Practice Questions
ATAR (Australia) · ATAR Physics · 145 free MCQs with instant results and detailed explanations.
145
Total
48
Easy
73
Medium
24
Hard
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Sample Questions from Linear Motion and Force
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
An object is moving in a straight line with a constant speed of 10 m/s. What is its acceleration?
A.
0 m/sยฒ
B.
10 m/sยฒ
C.
1 m/sยฒ
D.
5 m/sยฒ
Show Answer & Explanation
Correct Answer: A
An object moving at a constant speed has zero acceleration, as acceleration is the rate of change of velocity.
Q2
Easy
If a car accelerates from rest at a rate of 2 m/sยฒ for 5 seconds, what is the final velocity of the car?
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
Show Answer & Explanation
Correct Answer: B
Using the formula v = u + at, where u is initial velocity (0 m/s), a is acceleration (2 m/sยฒ), and t is time (5 s), the final velocity is 10 m/s.
Q3
Easy
A ball is thrown vertically upward with an initial velocity of 15 m/s. What will be its velocity at the highest point of its trajectory?
A.
0 m/s
B.
15 m/s
C.
30 m/s
D.
10 m/s
Show Answer & Explanation
Correct Answer: A
At the highest point of its trajectory, the velocity of the ball becomes 0 m/s before it starts falling back down due to gravity.
Q4
Medium
A car accelerates uniformly from rest to a velocity of 25 m/s in 10 seconds. What is the distance covered by the car during this time?
A.
125 m
B.
150 m
C.
200 m
D.
250 m
Show Answer & Explanation
Correct Answer: A
The distance covered can be calculated using the formula: distance = (initial velocity * time) + (1/2 * acceleration * time^2). Here, initial velocity is 0, and acceleration is 2.5 m/sยฒ, resulting in a distance of 125 m.
Q5
Medium
A 5 kg block is subjected to a net force of 20 N. What is its acceleration?
A.
2 m/sยฒ
B.
4 m/sยฒ
C.
10 m/sยฒ
D.
15 m/sยฒ
Show Answer & Explanation
Correct Answer: B
Using Newton's second law, F = ma, we can find acceleration (a) by rearranging the formula to a = F/m. Substituting the values gives a = 20 N / 5 kg = 4 m/sยฒ.
Q6
Medium
An object is moving in a straight line and its velocity-time graph is a straight line with a positive slope. What does this indicate about the object's motion?
A.
The object is at rest.
B.
The object is experiencing constant acceleration.
C.
The object is moving with constant velocity.
D.
The object is decelerating.
Show Answer & Explanation
Correct Answer: B
A straight line with a positive slope in a velocity-time graph indicates that the object's velocity is increasing uniformly over time, which signifies constant acceleration.
Q7
Medium
A satellite orbits the Earth in a circular path. What force is responsible for keeping it in orbit?
A.
Frictional force
B.
Gravitational force
C.
Electromagnetic force
D.
Centripetal force
Show Answer & Explanation
Correct Answer: B
The gravitational force between the satellite and the Earth provides the necessary centripetal force for the satellite to maintain its circular orbit, thus it is the gravitational force that keeps the satellite in orbit.
Q8
Hard
A block of mass 5 kg is placed on a frictionless incline of angle 30 degrees. What is the acceleration of the block down the incline?
A.
4.9 m/sยฒ
B.
9.8 m/sยฒ
C.
2.5 m/sยฒ
D.
7.5 m/sยฒ
Show Answer & Explanation
Correct Answer: A
The acceleration of the block down the incline is given by a = g * sin(ฮธ), where g = 9.8 m/sยฒ and ฮธ = 30 degrees. Therefore, a = 9.8 * sin(30ยฐ) = 9.8 * 0.5 = 4.9 m/sยฒ. Thus, the correct answer is 4.9 m/sยฒ.
Q9
Hard
A car accelerates uniformly from rest to a speed of 25 m/s over a distance of 100 m. What is the magnitude of the acceleration of the car?
A.
1.25 m/sยฒ
B.
2.5 m/sยฒ
C.
3.125 m/sยฒ
D.
5 m/sยฒ
Show Answer & Explanation
Correct Answer: C
Using the equation vยฒ = uยฒ + 2as, where v = final velocity, u = initial velocity, a = acceleration, and s = distance, we can find acceleration. Here, u = 0 m/s, v = 25 m/s, and s = 100 m. Rearranging gives a = (vยฒ - uยฒ)/(2s) = (25ยฒ - 0)/(2*100) = 625/200 = 3.125 m/sยฒ.
Q10
Hard
Two blocks, A (mass 2 kg) and B (mass 3 kg), are connected by a light inextensible string over a frictionless pulley. If block A is hanging and block B is on a table, what is the acceleration of the system when block A is released?
A.
1.5 m/sยฒ
B.
2.0 m/sยฒ
C.
3.0 m/sยฒ
D.
4.0 m/sยฒ
Show Answer & Explanation
Correct Answer: B
Using Newton's second law, the net force is the difference in weight between A and B, F_net = m_A * g - m_B * a, where a is the acceleration of the system. The total mass is m_A + m_B = 2 kg + 3 kg = 5 kg. Solving gives a = (m_A * g) / (m_A + m_B) = (2 kg * 9.8 m/sยฒ) / (5 kg) = 2.0 m/sยฒ.
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Linear Motion and Force โ ATAR (Australia) ATAR Physics Practice Questions Online
This page contains 145 practice MCQs for the chapter Linear Motion and Force in ATAR (Australia) ATAR Physics. The questions are organized by difficulty โ 48 easy, 73 medium, 24 hard โ so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.