Solutions Practice Questions

Class 12 · Chemistry · 1874 free MCQs with instant results and detailed explanations.

1874
Total
603
Easy
914
Medium
357
Hard

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Topics in Solutions

Concentration Terms 301
Ideal and Non-ideal Solutions 571
Raoult's Law 495
Colligative Properties 507

Sample Questions from Solutions

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Q1
Easy
Which of the following solutions has the highest concentration if all are 1 liter in volume?
A. 1 mole of NaCl
B. 0.5 moles of KCl
C. 2 moles of CaCl2
D. 0.75 moles of MgCl2
Show Answer & Explanation
Correct Answer: C
The concentration in terms of molarity is highest for 2 moles of CaCl2 because it dissociates into 3 ions (2 moles = 6 equivalents in total).
Q2
Easy
Which of the following is a common unit for expressing concentration?
A. Molarity
B. Velocity
C. Temperature
D. Pressure
Show Answer & Explanation
Correct Answer: A
Molarity is a widely used unit for concentration, defined as moles of solute per liter of solution.
Q3
Easy
If 10 g of NaCl is dissolved in 1 L of water, what is its molarity? (Molar mass of NaCl = 58.5 g/mol)
A. 0.171 M
B. 0.3 M
C. 0.5 M
D. 1 M
Show Answer & Explanation
Correct Answer: A
Molarity = moles of solute/volume of solution in liters. 10 g NaCl = 10/58.5 = 0.171 moles.
Q4
Medium
Calculate the number of moles in 150 grams of glucose (C6H12O6). Molar mass of glucose is 180 g/mol.
A. 0.5 moles
B. 0.75 moles
C. 1.0 moles
D. 1.5 moles
Show Answer & Explanation
Correct Answer: A
Number of moles = mass / molar mass. Here, 150 g / 180 g/mol = 0.833 moles.
Q5
Medium
If 4 g of KBr is dissolved in 100 mL of solution, what is its molarity? (Molar mass of KBr = 119 g/mol)
A. 0.2 M
B. 0.5 M
C. 1.0 M
D. 1.5 M
Show Answer & Explanation
Correct Answer: A
Moles of KBr = 4 g / 119 g/mol = 0.0336 moles. Molarity = moles/volume(L) = 0.0336/0.1 = 0.336 M.
Q6
Medium
Which of the following terms represents the amount of solute per 100 g of the solution?
A. Molarity
B. Molality
C. Mass percentage
D. Mole fraction
Show Answer & Explanation
Correct Answer: C
Mass percentage is defined as the mass of solute divided by the mass of solution times 100.
Q7
Medium
What is the mole fraction of solute in a solution containing 3 moles of solute and 6 moles of solvent?
A. 0.25
B. 0.33
C. 0.50
D. 0.67
Show Answer & Explanation
Correct Answer: A
Mole fraction of solute = moles of solute / (moles of solute + moles of solvent). Here, 3 / (3 + 6) = 0.333.
Q8
Hard
What is the molality of a solution containing 10 g of NaCl in 200 g of water? (Molar mass of NaCl = 58.5 g/mol)
A. 0.857 m
B. 1.000 m
C. 0.500 m
D. 1.500 m
Show Answer & Explanation
Correct Answer: A
Molality (m) is defined as moles of solute per kilogram of solvent. Here, moles of NaCl = 10g / 58.5g/mol = 0.171 mol. The mass of water is 0.200 kg, so molality = 0.171 mol / 0.200 kg = 0.857 m.
Q9
Hard
If the density of a solution is 1.2 g/mL and contains 2 moles of solute in 1 L of solution, what is the molarity?
A. 2 M
B. 1.67 M
C. 1.5 M
D. 2.5 M
Show Answer & Explanation
Correct Answer: A
Molarity (M) is defined as moles of solute per liter of solution. Here, it is given directly as 2 moles in 1 L, hence M = 2 M.
Q10
Hard
What is the concentration in mass percent of a solution containing 10 g of NaOH in 90 g of water?
A. 10%
B. 20%
C. 9.09%
D. 1.11%
Show Answer & Explanation
Correct Answer: A
Mass percent concentration is calculated as (mass of solute / total mass of solution) * 100. Here, mass of solution = 10 g + 90 g = 100 g, so mass percent = (10/100) * 100 = 10%.

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Solutions — Class 12 Chemistry Practice Questions Online

This page contains 1874 practice MCQs for the chapter Solutions in Class 12 Chemistry. The questions are organized by difficulty — 603 easy, 914 medium, 357 hard — so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 4 topics, giving you comprehensive coverage of the entire chapter.