Gravitation Practice Questions

HSC/SSC (Bangladesh) · HSC Physics · 150 free MCQs with instant results and detailed explanations.

150
Total
50
Easy
80
Medium
20
Hard

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Sample Questions from Gravitation

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Q1
Easy
What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 meters? (Use G = 6.67 x 10^-11 Nmยฒ/kgยฒ)
A. 1.67 x 10^-10 N
B. 1.67 x 10^-9 N
C. 3.34 x 10^-10 N
D. 3.34 x 10^-9 N
Show Answer & Explanation
Correct Answer: A
The gravitational force can be calculated using Newton's law of universal gravitation: F = G * (m1 * m2) / rยฒ. Plugging in the values gives F = 6.67 x 10^-11 * (5 * 10) / (2ยฒ) = 1.67 x 10^-10 N.
Q2
Easy
If the distance between the Earth and a satellite is doubled, what happens to the gravitational force between them?
A. It doubles
B. It quadruples
C. It halves
D. It reduces to one-fourth
Show Answer & Explanation
Correct Answer: D
According to the inverse square law, the gravitational force is inversely proportional to the square of the distance. If the distance is doubled, the force reduces to (1/2)ยฒ = 1/4 of the original force.
Q3
Easy
Which of the following statements correctly describes the effect of gravity on a freely falling object?
A. The object accelerates at 9.8 m/sยฒ towards the center of the Earth.
B. The object moves at a constant speed.
C. The object decelerates as it falls.
D. The object experiences no force acting on it.
Show Answer & Explanation
Correct Answer: A
According to the laws of motion, a freely falling object experiences a constant acceleration of approximately 9.8 m/sยฒ towards the Earth due to gravity.
Q4
Medium
What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 meters? (G = 6.67 x 10^-11 N mยฒ/kgยฒ)
A. 8.34 x 10^-10 N
B. 1.67 x 10^-10 N
C. 3.34 x 10^-10 N
D. 2.00 x 10^-10 N
Show Answer & Explanation
Correct Answer: A
Using Newton's law of universal gravitation, F = G * (m1 * m2) / rยฒ: F = (6.67 x 10^-11) * (5 * 10) / (2ยฒ) = 8.34 x 10^-10 N.
Q5
Medium
If the distance between two objects is doubled, how does the gravitational force between them change?
A. It doubles
B. It is halved
C. It is quartered
D. It remains the same
Show Answer & Explanation
Correct Answer: C
According to the law of universal gravitation, F is inversely proportional to the square of the distance; if r is doubled, F becomes 1/4 of its original value.
Q6
Medium
Which of the following statements about gravitational potential energy is true?
A. It is always negative.
B. It increases as the distance between two masses decreases.
C. It remains constant when mass is constant and distance is variable.
D. It depends only on the mass of the objects.
Show Answer & Explanation
Correct Answer: B
Gravitational potential energy decreases (becomes more negative) as the distance between two masses decreases, indicating that energy is released when they come closer.
Q7
Medium
A satellite is in a circular orbit around the Earth. What is the relationship between the satellite's orbital speed and the Earth's gravitational force?
A. Orbital speed is independent of gravitational force.
B. Orbital speed increases with distance from Earth.
C. Gravitational force provides the centripetal force required for circular motion.
D. Orbital speed is constant for all satellites regardless of their mass.
Show Answer & Explanation
Correct Answer: C
The gravitational force acting on the satellite provides the necessary centripetal force to maintain its circular orbit, thus directly relating the two.
Q8
Hard
Two objects, A and B, each with a mass of 10 kg, are placed 1 meter apart. What is the gravitational force between them?
A. 0.0667 N
B. 0.00067 N
C. 0.1 N
D. 0.001 N
Show Answer & Explanation
Correct Answer: A
The gravitational force can be calculated using Newton's law of gravitation: F = G(m1 * m2) / r^2. Substituting G = 6.67 x 10^-11 N(m/kg)^2, m1 = m2 = 10 kg, and r = 1 m gives F = (6.67 x 10^-11 * 10 * 10) / (1^2) = 0.0667 N.
Q9
Hard
Two objects, A and B, have masses of 5 kg and 10 kg, respectively. If the distance between their centers is 2 meters, calculate the gravitational force between them (G = 6.674 ร— 10^-11 N mยฒ/kgยฒ).
A. 1.67 ร— 10^-10 N
B. 3.34 ร— 10^-10 N
C. 6.67 ร— 10^-11 N
D. 1.34 ร— 10^-10 N
Show Answer & Explanation
Correct Answer: B
The gravitational force can be calculated using the formula F = G(m1*m2)/rยฒ. Substituting the values, F = (6.674 ร— 10^-11)(5)(10)/(2ยฒ) = 3.34 ร— 10^-10 N, hence the correct answer is B.
Q10
Hard
If the radius of a planet is doubled and its mass remains constant, what will be the effect on the gravitational acceleration at its surface?
A. It will double.
B. It will remain the same.
C. It will become half.
D. It will become one-fourth.
Show Answer & Explanation
Correct Answer: D
The gravitational acceleration is given by g = G*M/rยฒ. If the radius r is doubled (r โ†’ 2r), g becomes G*M/(2r)ยฒ = G*M/(4rยฒ). Hence, g is reduced to one-fourth of its original value, making option D correct.

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Gravitation โ€” HSC/SSC (Bangladesh) HSC Physics Practice Questions Online

This page contains 150 practice MCQs for the chapter Gravitation in HSC/SSC (Bangladesh) HSC Physics. The questions are organized by difficulty โ€” 50 easy, 80 medium, 20 hard โ€” so you can choose the right level for your preparation.

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