Laws of Motion Practice Questions

HSC/SSC (Bangladesh) · HSC Physics · 147 free MCQs with instant results and detailed explanations.

147
Total
52
Easy
72
Medium
23
Hard

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Sample Questions from Laws of Motion

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Q1
Easy
An object is moving in a straight line with a constant speed. Which of the following statements is true about the net force acting on the object?
A. The net force is zero.
B. The net force is equal to its weight.
C. The net force is equal to the speed of the object.
D. The net force is acting in the direction of motion.
Show Answer & Explanation
Correct Answer: A
When an object moves with constant speed in a straight line, it is in equilibrium, meaning the net force acting on it is zero. This is a fundamental concept in Newton's first law of motion.
Q2
Easy
A car accelerates from rest at a constant rate of 2 m/sยฒ. How far does it travel in 5 seconds?
A. 25 m
B. 20 m
C. 10 m
D. 50 m
Show Answer & Explanation
Correct Answer: A
Using the equation of motion, distance = initial velocity ร— time + 0.5 ร— acceleration ร— timeยฒ, we have: distance = 0 ร— 5 + 0.5 ร— 2 ร— 5ยฒ = 25 m.
Q3
Easy
If a 10 kg block is pulled horizontally with a force of 50 N and there is a frictional force of 20 N opposing the motion, what will be the acceleration of the block?
A. 3 m/sยฒ
B. 5 m/sยฒ
C. 2 m/sยฒ
D. 4 m/sยฒ
Show Answer & Explanation
Correct Answer: A
First calculate the net force: Net force = applied force - frictional force = 50 N - 20 N = 30 N. Then use Newton's second law: F = ma, thus acceleration a = F/m = 30 N / 10 kg = 3 m/sยฒ.
Q4
Medium
What is the net force acting on a 5 kg object accelerating at 3 m/sยฒ?
A. 10 N
B. 15 N
C. 8 N
D. 5 N
Show Answer & Explanation
Correct Answer: B
According to Newton's second law, F = ma. Here, F = 5 kg * 3 m/sยฒ = 15 N.
Q5
Medium
A ball is thrown vertically upward with a velocity of 30 m/s. How high will it rise before coming to a momentary stop? (Take g = 10 m/sยฒ)
A. 45 m
B. 90 m
C. 60 m
D. 75 m
Show Answer & Explanation
Correct Answer: A
Using the formula h = vยฒ/(2g), we find h = (30)ยฒ/(2*10) = 45 m.
Q6
Medium
A bicycle accelerates uniformly from rest to a speed of 10 m/s in 5 seconds. What is the distance covered by the bicycle during this time?
A. 25 m
B. 50 m
C. 20 m
D. 30 m
Show Answer & Explanation
Correct Answer: A
Using the formula d = ut + (1/2)atยฒ, with u = 0, we find d = 0 + (1/2)(2 m/sยฒ)(5ยฒ) = 25 m.
Q7
Medium
A car accelerates from rest at a constant rate of 2 m/sยฒ. How far will it travel in 5 seconds?
A. 25 meters
B. 20 meters
C. 10 meters
D. 30 meters
Show Answer & Explanation
Correct Answer: A
The distance traveled under constant acceleration can be calculated using the formula: distance = 0.5 ร— acceleration ร— timeยฒ. Here, distance = 0.5 ร— 2 m/sยฒ ร— (5 s)ยฒ = 25 meters.
Q8
Hard
A 5 kg block is sliding down a frictionless incline at an angle of 30 degrees. What is the acceleration of the block down the incline?
A. 4.9 m/sยฒ
B. 9.8 m/sยฒ
C. 2.5 m/sยฒ
D. 7.5 m/sยฒ
Show Answer & Explanation
Correct Answer: A
The acceleration down a frictionless incline is given by g * sin(ฮธ). Here, g = 9.8 m/sยฒ and ฮธ = 30ยฐ, thus a = 9.8 * sin(30ยฐ) = 4.9 m/sยฒ.
Q9
Hard
A 10 kg object is pushed on a frictionless surface with a force of 50 N. Calculate the acceleration of the object.
A. 5 m/sยฒ
B. 10 m/sยฒ
C. 15 m/sยฒ
D. 20 m/sยฒ
Show Answer & Explanation
Correct Answer: A
Using Newton's second law, F = ma, the acceleration 'a' can be calculated as a = F/m = 50 N / 10 kg = 5 m/sยฒ. Thus, the correct answer is A.
Q10
Hard
A car travels around a circular track of radius 200 m at a constant speed of 30 m/s. What is the centripetal acceleration of the car?
A. 4.5 m/sยฒ
B. 6.75 m/sยฒ
C. 9 m/sยฒ
D. 12 m/sยฒ
Show Answer & Explanation
Correct Answer: C
Centripetal acceleration (a_c) is given by the formula a_c = vยฒ/r. Here, v = 30 m/s and r = 200 m, so a_c = (30 m/s)ยฒ / 200 m = 9 m/sยฒ. Hence, the correct answer is C.

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Laws of Motion โ€” HSC/SSC (Bangladesh) HSC Physics Practice Questions Online

This page contains 147 practice MCQs for the chapter Laws of Motion in HSC/SSC (Bangladesh) HSC Physics. The questions are organized by difficulty โ€” 52 easy, 72 medium, 23 hard โ€” so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.