Magnetism Practice Questions

HSC/SSC (Bangladesh) · HSC Physics · 149 free MCQs with instant results and detailed explanations.

149
Total
49
Easy
71
Medium
29
Hard

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Sample Questions from Magnetism

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Q1
Easy
What is the primary reason magnetic poles always come in pairs?
A. Magnetic monopoles do not exist in nature.
B. Magnetic materials are always neutral.
C. Magnetic forces are stronger at the poles.
D. Magnetic fields cancel each other out.
Show Answer & Explanation
Correct Answer: A
Magnetic monopoles, which would be isolated north or south poles, have not been observed in nature. All magnets have both a north and south pole.
Q2
Easy
If a current-carrying wire is placed in a magnetic field, what will happen to the wire?
A. It will heat up.
B. It will experience a force.
C. It will become magnetized.
D. Nothing will happen.
Show Answer & Explanation
Correct Answer: B
According to the motor effect, a current-carrying conductor in a magnetic field experiences a force perpendicular to both the field and the current.
Q3
Easy
Which of the following materials can be classified as a ferromagnetic material?
A. Copper
B. Aluminum
C. Iron
D. Gold
Show Answer & Explanation
Correct Answer: C
Iron is a ferromagnetic material, meaning it can be magnetized and has strong magnetic properties, unlike copper, aluminum, and gold.
Q4
Medium
What happens to the magnetic field strength of a solenoid if the number of turns is doubled while the current remains constant?
A. It doubles
B. It remains the same
C. It halves
D. It quadruples
Show Answer & Explanation
Correct Answer: A
Doubling the number of turns in a solenoid while keeping the current constant increases the magnetic field strength because the magnetic field inside a solenoid is directly proportional to the number of turns per unit length.
Q5
Medium
A current-carrying wire is placed in a magnetic field. What is the direction of the force experienced by the wire?
A. Parallel to the current direction
B. Opposite to the magnetic field direction
C. Perpendicular to both the current and magnetic field
D. In the direction of the magnetic field
Show Answer & Explanation
Correct Answer: C
The force on a current-carrying conductor in a magnetic field is given by Flemingโ€™s Left Hand Rule, which states that the force is perpendicular to both the magnetic field and current direction.
Q6
Medium
If a magnet is cut into two equal halves, what will be true about the two pieces?
A. Each half becomes a magnet with one pole
B. Each half becomes a complete magnet with both poles
C. One half will have only a north pole
D. One half will have only a south pole
Show Answer & Explanation
Correct Answer: B
When a magnet is cut, each piece will become a complete magnet with both a north and a south pole. The magnetic domains reorganize themselves to maintain this property.
Q7
Medium
A magnetic field strength of 0.5 T is applied to a circular loop of radius 0.1 m carrying a current of 10 A. What is the torque acting on the loop?
A. 0.05 Nm
B. 0.1 Nm
C. 0.2 Nm
D. 0.25 Nm
Show Answer & Explanation
Correct Answer: C
The torque (ฯ„) on a current loop in a magnetic field is given by ฯ„ = nIA B sin(ฮธ). For a circular loop, n = 1, A = ฯ€rยฒ, and ฮธ = 90 degrees (sin(90) = 1). Calculating gives ฯ„ = 1 * 10 * ฯ€(0.1)ยฒ * 0.5 = 0.2 Nm.
Q8
Hard
A circular loop of radius 0.1 m carries a current of 5 A. Calculate the magnetic field at the center of the loop. Use the formula B = (ฮผโ‚€ * I) / (2 * R) where ฮผโ‚€ = 4ฯ€ ร— 10โปโท T m/A.
A. 3.14 ร— 10โปโถ T
B. 2.5 ร— 10โปโถ T
C. 1.57 ร— 10โปโถ T
D. 7.85 ร— 10โปโถ T
Show Answer & Explanation
Correct Answer: A
Using the formula B = (ฮผโ‚€ * I) / (2 * R), we substitute ฮผโ‚€ = 4ฯ€ ร— 10โปโท, I = 5 A, and R = 0.1 m. This gives B = (4ฯ€ ร— 10โปโท * 5) / (2 * 0.1) = 3.14 ร— 10โปโถ T.
Q9
Hard
A solenoid of length 2 m and cross-sectional area of 0.01 mยฒ has 200 turns. If a current of 3 A flows through the solenoid, what is the magnetic field inside it? Use the formula B = (ฮผโ‚€ * n * I) where n is the number of turns per unit length.
A. 3.77 ร— 10โปโถ T
B. 3.77 ร— 10โปยณ T
C. 1.5 ร— 10โปยณ T
D. 7.54 ร— 10โปโถ T
Show Answer & Explanation
Correct Answer: B
To find the magnetic field, first calculate n = number of turns / length = 200 / 2 = 100 turns/m. Then, B = ฮผโ‚€ * n * I = (4ฯ€ ร— 10โปโท) * 100 * 3 = 3.77 ร— 10โปยณ T.
Q10
Hard
A circular loop of radius 10 cm carries a current of 5 A. Calculate the magnetic field strength at the center of the loop. (Use ฮผโ‚€ = 4ฯ€ ร— 10โปโท T m/A)
A. 1.57 ร— 10โปโต T
B. 3.14 ร— 10โปโต T
C. 7.85 ร— 10โปโต T
D. 2.51 ร— 10โปโต T
Show Answer & Explanation
Correct Answer: B
The magnetic field at the center of a circular loop is given by B = (ฮผโ‚€ * I) / (2 * R). Here, B = (4ฯ€ ร— 10โปโท T m/A * 5 A) / (2 * 0.1 m) = 3.14 ร— 10โปโต T.

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Magnetism โ€” HSC/SSC (Bangladesh) HSC Physics Practice Questions Online

This page contains 149 practice MCQs for the chapter Magnetism in HSC/SSC (Bangladesh) HSC Physics. The questions are organized by difficulty โ€” 49 easy, 71 medium, 29 hard โ€” so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.