Motion in One Dimension Practice Questions

HSC/SSC (Bangladesh) · HSC Physics · 138 free MCQs with instant results and detailed explanations.

138
Total
53
Easy
68
Medium
17
Hard

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Sample Questions from Motion in One Dimension

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Q1
Easy
An object moves in a straight line with a constant speed of 20 m/s. How far will it travel in 5 seconds?
A. 100 m
B. 80 m
C. 60 m
D. 120 m
Show Answer & Explanation
Correct Answer: A
Using the formula distance = speed ร— time, we calculate: distance = 20 m/s ร— 5 s = 100 m. Hence, the object travels 100 meters.
Q2
Easy
If a car accelerates from rest at a rate of 2 m/sยฒ, how fast will it be moving after 8 seconds?
A. 16 m/s
B. 24 m/s
C. 32 m/s
D. 8 m/s
Show Answer & Explanation
Correct Answer: A
Using the formula final velocity = initial velocity + (acceleration ร— time), we find: final velocity = 0 + (2 m/sยฒ ร— 8 s) = 16 m/s.
Q3
Easy
If a train travels at a constant speed of 90 km/h, how far will it travel in 2 hours?
A. 90 km
B. 150 km
C. 180 km
D. 200 km
Show Answer & Explanation
Correct Answer: C
Distance is calculated using the formula: distance = speed ร— time. Here, distance = 90 km/h ร— 2 h = 180 km.
Q4
Medium
An object moves in a straight line with an initial velocity of 4 m/s and accelerates at -2 m/sยฒ. What is its velocity after 3 seconds?
A. 0 m/s
B. 2 m/s
C. 4 m/s
D. 10 m/s
Show Answer & Explanation
Correct Answer: B
Using the formula v = u + at, where u = 4 m/s, a = -2 m/sยฒ, and t = 3 s, we find v = 4 + (-2)*3 = 4 - 6 = -2 m/s, which indicates reverse direction.
Q5
Medium
An object moves in a straight line with a velocity of 12 m/s. If it accelerates at a rate of -2 m/sยฒ, what will be its velocity after 5 seconds?
A. 2 m/s
B. 12 m/s
C. 22 m/s
D. 7 m/s
Show Answer & Explanation
Correct Answer: A
To find the final velocity, we use the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. Thus, v = 12 m/s + (-2 m/sยฒ * 5 s) = 12 m/s - 10 m/s = 2 m/s.
Q6
Medium
A car starts from rest and accelerates uniformly at 2 m/sยฒ. How far does it travel in 5 seconds?
A. 25 meters
B. 10 meters
C. 50 meters
D. 15 meters
Show Answer & Explanation
Correct Answer: A
Using the formula for distance under uniform acceleration, s = ut + 0.5atยฒ, where u = 0, a = 2 m/sยฒ, and t = 5 s, we find s = 0 + 0.5 * 2 * (5)ยฒ = 25 meters.
Q7
Medium
A car accelerates uniformly from rest to a speed of 25 m/s in 10 seconds. What is the distance traveled by the car during this time?
A. 125 m
B. 250 m
C. 100 m
D. 150 m
Show Answer & Explanation
Correct Answer: A
The distance traveled can be calculated using the formula: Distance = initial velocity ร— time + 0.5 ร— acceleration ร— timeยฒ. Here, initial velocity is 0, final velocity is 25 m/s, and time is 10 s. The acceleration is (25 m/s) / (10 s) = 2.5 m/sยฒ. Thus, distance = 0 + 0.5 ร— 2.5 ร— (10)ยฒ = 125 m.
Q8
Hard
A car accelerates uniformly from rest to a speed of 30 m/s in 10 seconds. What is the total distance covered by the car during this time?
A. 150 m
B. 120 m
C. 100 m
D. 200 m
Show Answer & Explanation
Correct Answer: A
Using the formula for distance covered under uniform acceleration, s = ut + (1/2)atยฒ. Here, u = 0, a = (v - u)/t = 3 m/sยฒ, and t = 10 s. Thus, s = 0 + (1/2)(3)(10)ยฒ = 150 m.
Q9
Hard
A car accelerates uniformly from rest to a speed of 30 m/s in 10 seconds. What is the total distance covered by the car during this time?
A. 150 m
B. 300 m
C. 450 m
D. 600 m
Show Answer & Explanation
Correct Answer: A
The distance covered under uniform acceleration can be calculated using the formula: distance = (initial velocity * time) + (1/2 * acceleration * time^2). With initial velocity = 0, we first find acceleration as 30 m/s divided by 10 s = 3 m/sยฒ. So, distance = (0 * 10) + (1/2 * 3 * 10^2) = 150 m.
Q10
Hard
An object is thrown vertically upward with an initial velocity of 40 m/s. What is the maximum height reached by the object? (Assume g = 10 m/sยฒ)
A. 80 m
B. 160 m
C. 200 m
D. 320 m
Show Answer & Explanation
Correct Answer: B
The maximum height can be determined using the formula: height = (initial velocityยฒ) / (2 * g). Here, height = (40 m/s)ยฒ / (2 * 10 m/sยฒ) = 160 m. This shows the object rises until its velocity becomes zero due to gravity acting against it.

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Motion in One Dimension โ€” HSC/SSC (Bangladesh) HSC Physics Practice Questions Online

This page contains 138 practice MCQs for the chapter Motion in One Dimension in HSC/SSC (Bangladesh) HSC Physics. The questions are organized by difficulty โ€” 53 easy, 68 medium, 17 hard โ€” so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.