Motion in Two Dimensions Practice Questions
HSC/SSC (Bangladesh) · HSC Physics · 150 free MCQs with instant results and detailed explanations.
150
Total
50
Easy
65
Medium
35
Hard
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Sample Questions from Motion in Two Dimensions
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Q1
Easy
A car travels 120 meters north in 4 seconds. What is its average velocity?
A.
30 m/s north
B.
40 m/s north
C.
20 m/s north
D.
10 m/s north
Show Answer & Explanation
Correct Answer: A
Average velocity is calculated by dividing the total displacement by the total time. Here, the displacement is 120 meters north and the time is 4 seconds, leading to an average velocity of 120/4 = 30 m/s north.
Q2
Easy
A cyclist moves east for 2 km, then turns north for 3 km. What is the cyclist's resultant displacement from the starting point?
A.
3.6 km
B.
4 km
C.
5 km
D.
2 km
Show Answer & Explanation
Correct Answer: C
To find the resultant displacement, we apply the Pythagorean theorem. The displacement east is 2 km and north is 3 km. Resultant displacement = โ(2ยฒ + 3ยฒ) = โ(4 + 9) = โ13 = 5 km.
Q3
Easy
A car travels 100 meters north and then 100 meters east. What is the magnitude of its displacement from the starting point?
A.
100โ2 meters
B.
200 meters
C.
100 meters
D.
150 meters
Show Answer & Explanation
Correct Answer: A
The displacement is the straight-line distance from the starting point to the endpoint. Using the Pythagorean theorem, the displacement is โ(100ยฒ + 100ยฒ) = 100โ2 meters.
Q4
Medium
A projectile is launched from the ground with an initial velocity of 40 m/s at an angle of 30 degrees to the horizontal. What is the maximum height reached by the projectile?
A.
80 m
B.
40 m
C.
60 m
D.
20 m
Show Answer & Explanation
Correct Answer: A
The maximum height (H) can be calculated using the formula H = (v^2 * sin^2(ฮธ)) / (2g). Here, v = 40 m/s, ฮธ = 30 degrees, and g = 9.8 m/sยฒ. Substituting these values yields H = (40^2 * (0.5)^2) / (2 * 9.8) = 80 m.
Q5
Medium
An airplane is flying horizontally at a height of 500 m with a speed of 200 m/s. How far will it travel horizontally before it hits the ground?
A.
2000 m
B.
1000 m
C.
500 m
D.
1500 m
Show Answer & Explanation
Correct Answer: A
To find the horizontal distance, we first calculate the time (t) it takes to hit the ground using the formula t = โ(2h/g). Here, h = 500 m and g = 9.8 m/sยฒ. t = โ(2 * 500 / 9.8) โ 10.1 s. Then, horizontal distance = speed * time = 200 m/s * 10.1 s = 2000 m.
Q6
Medium
A stone is thrown from the top of a cliff with an initial velocity of 15 m/s at an angle of 45 degrees. What is the range of the stone when it hits the ground?
A.
30 m
B.
45 m
C.
50 m
D.
60 m
Show Answer & Explanation
Correct Answer: B
To find the range (R), we use the formula R = (v^2 * sin(2ฮธ)) / g. Here, v = 15 m/s, ฮธ = 45 degrees, and g = 9.8 m/sยฒ. Thus, R = (15^2 * sin(90)) / 9.8 = 45 m.
Q7
Medium
A projectile is launched at an angle of 30ยฐ with an initial velocity of 20 m/s. What is the maximum height reached by the projectile? (Assume g = 9.8 m/sยฒ)
A.
5.1 m
B.
10.2 m
C.
20.4 m
D.
7.3 m
Show Answer & Explanation
Correct Answer: A
The maximum height (H) is calculated using H = (vยฒ * sinยฒ(ฮธ)) / (2g). Here, v = 20 m/s, ฮธ = 30ยฐ, and g = 9.8 m/sยฒ, resulting in H = (20ยฒ * (1/4)) / (2 * 9.8) = 5.1 m.
Q8
Hard
A projectile is launched with an initial velocity of 40 m/s at an angle of 30ยฐ to the horizontal. What is the maximum height reached by the projectile? (Use g = 10 m/sยฒ)
A.
80 m
B.
40 m
C.
60 m
D.
20 m
Show Answer & Explanation
Correct Answer: B
The maximum height (H) of a projectile can be calculated using the formula H = (uยฒ * sinยฒฮธ) / (2g). Here, u = 40 m/s, ฮธ = 30ยฐ, and g = 10 m/sยฒ. Thus, H = (40ยฒ * (1/2)) / (20) = 40 m. Therefore, the correct answer is 40 m.
Q9
Hard
A car moving at 30 m/s is approaching a traffic signal. At a distance of 100 m from the signal, it starts decelerating at 2 m/sยฒ. How much time will it take for the car to stop before reaching the signal?
A.
5 seconds
B.
10 seconds
C.
7.5 seconds
D.
12 seconds
Show Answer & Explanation
Correct Answer: C
Using the equation of motion: vยฒ = uยฒ + 2as, where v = final velocity (0 m/s), u = initial velocity (30 m/s), and a = -2 m/sยฒ, we find the distance covered in stopping. The car stops after covering 113.25 m, so it will not stop in time. However, calculating time using t = (v - u) / a gives 15 seconds. The time before reaching the signal is calculated as: d = ut + (1/2)atยฒ, solving gives t = 7.5 seconds to cover 100 m before stopping.
Q10
Hard
A projectile is launched from the ground at an angle of 30ยฐ with an initial speed of 20 m/s. What is the maximum height reached by the projectile? (Assume g = 9.81 m/sยฒ)
A.
10.2 m
B.
20.4 m
C.
5.1 m
D.
15.3 m
Show Answer & Explanation
Correct Answer: A
The maximum height (H) can be calculated using the formula H = (v^2 * sinยฒฮธ) / (2g). Here, v = 20 m/s, ฮธ = 30ยฐ, and g = 9.81 m/sยฒ. Plugging in the values, H = (20ยฒ * (1/4)) / (2 * 9.81) = 10.2 m.
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Motion in Two Dimensions โ HSC/SSC (Bangladesh) HSC Physics Practice Questions Online
This page contains 150 practice MCQs for the chapter Motion in Two Dimensions in HSC/SSC (Bangladesh) HSC Physics. The questions are organized by difficulty โ 50 easy, 65 medium, 35 hard โ so you can choose the right level for your preparation.
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