Electrostatics Practice Questions
JEE · Physics · 1650 free MCQs with instant results and detailed explanations.
1650
Total
379
Easy
715
Medium
556
Hard
Start Practicing Electrostatics
Take a timed quiz or customize your practice session
Topics in Electrostatics
Coulomb's Law
249
Electric Field
228
Gauss's Law
245
Electric Potential
243
Capacitors
216
Dielectrics
261
Energy Stored in Capacitor
208
Sample Questions from Electrostatics
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
If the distance between two point charges is halved, how does the electrostatic force between them change?
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It reduces by half
Show Answer & Explanation
Correct Answer: B
According to Coulomb's Law, the force is inversely proportional to the square of the distance. Halving the distance results in the force increasing by a factor of 4.
Q2
Easy
Which of the following statements about Coulombโs Law is true?
A.
It applies only to stationary charges
B.
It is valid in a vacuum only
C.
It can be applied to any two charges regardless of their motion
D.
It describes the gravitational force between two charges
Show Answer & Explanation
Correct Answer: C
Coulomb's Law is applicable to any two charged objects, irrespective of whether they are stationary or in motion.
Q3
Easy
What is the direction of the electrostatic force experienced by a positive charge in the vicinity of another positive charge?
A.
Towards the positive charge
B.
Away from the positive charge
C.
Perpendicular to the line joining the charges
D.
Depends on the distance between the charges
Show Answer & Explanation
Correct Answer: B
Like charges repel each other. Therefore, a positive charge will experience a force away from another positive charge.
Q4
Medium
Two charges, +3 ยตC and -3 ยตC, are placed 10 cm apart in a vacuum. What is the force exerted on each charge?
A.
1.08 N
B.
0.81 N
C.
2.16 N
D.
0.54 N
Show Answer & Explanation
Correct Answer: A
Using Coulomb's law, F = k * |q1 * q2| / rยฒ, where k = 9 ร 10^9 N mยฒ/Cยฒ, q1 = 3 ร 10^-6 C, q2 = 3 ร 10^-6 C, and r = 0.1 m, the force calculates to 1.08 N.
Q5
Medium
If the distance between two point charges is halved, how does the electrostatic force change?
A.
It becomes four times larger
B.
It becomes twice as large
C.
It remains the same
D.
It becomes half
Show Answer & Explanation
Correct Answer: A
According to Coulomb's law, the force is inversely proportional to the square of the distance. Halving the distance results in a fourfold increase in force.
Q6
Medium
Three charges are placed at the vertices of an equilateral triangle with sides of 0.5 m. If the charges are +2 ยตC, -2 ยตC, and +2 ยตC, what is the net force on the negative charge?
A.
0.08 N
B.
0.04 N
C.
0.12 N
D.
0.16 N
Show Answer & Explanation
Correct Answer: A
Calculate the forces due to each charge on the negative charge, then use vector addition to find the net force. The forces from the two positive charges will add up.
Q7
Medium
If two point charges of +2 ยตC and -2 ยตC are placed 1 m apart, what is the direction of the force on the positive charge?
A.
Towards the negative charge
B.
Away from the negative charge
C.
No force
D.
Towards the positive charge
Show Answer & Explanation
Correct Answer: A
The positive charge experiences an attractive force towards the negative charge due to electrostatic attraction.
Q8
Hard
If the force between two point charges is F when they are at a distance r apart, what will be the new force when the distance is doubled?
A.
F/2
B.
F/4
C.
F
D.
2F
Show Answer & Explanation
Correct Answer: B
According to Coulomb's law, the force is inversely proportional to the square of the distance. Doubling the distance results in the force being reduced to a quarter of the original.
Q9
Hard
A charge of +3ฮผC is placed at the origin and a charge of -2ฮผC is placed at (0, 1m) on the y-axis. What is the net electric field at the point (0, 0.5m)?
A.
0 N/C
B.
1800 N/C upward
C.
1800 N/C downward
D.
3000 N/C upward
Show Answer & Explanation
Correct Answer: B
The electric field due to the positive charge at (0, 0.5m) is directed upward, while the field due to the negative charge is directed downward and is less in magnitude.
Q10
Hard
Two identical positive charges of magnitude q are placed at a distance d apart. What minimum potential energy configuration would allow them to remain in equilibrium against repulsion?
A.
Placing a negative charge between them
B.
Increasing their distance to 2d
C.
Surrounding them with a dielectric
D.
Using a magnetic field
Show Answer & Explanation
Correct Answer: A
A negative charge between the two positive charges will attract both and can create a stable equilibrium by counteracting the repulsive forces.
Showing 10 of 1650 questions. Start a quiz to practice all questions with scoring and timer.
Practice All 1650 Questions →Other JEE Subjects
Electrostatics โ JEE Physics Practice Questions Online
This page contains 1650 practice MCQs for the chapter Electrostatics in JEE Physics. The questions are organized by difficulty โ 379 easy, 715 medium, 556 hard โ so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 7 topics, giving you comprehensive coverage of the entire chapter.