Electrostatics and Current Electricity Practice Questions
JEE · Physics · 1435 free MCQs with instant results and detailed explanations.
1435
Total
330
Easy
621
Medium
484
Hard
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Topics in Electrostatics and Current Electricity
Capacitors
285
Gauss's Law
322
Coulomb's Law
303
Kirchhoff's Laws
270
Ohm's Law
255
Sample Questions from Electrostatics and Current Electricity
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
If the distance between two charges is halved, how does the force between them change?
A.
Increases by 4 times
B.
Increases by 2 times
C.
Decreases by 4 times
D.
Remains the same
Show Answer & Explanation
Correct Answer: A
According to Coulomb's Law, force is inversely proportional to the square of the distance.
Q2
Easy
Two charges, +5 ยตC and +10 ยตC, are 3 meters apart. What is the magnitude of the net force on each charge?
A.
0.15 N
B.
0.30 N
C.
0.45 N
D.
0.20 N
Show Answer & Explanation
Correct Answer: B
Calculate the forces using Coulomb's Law and recognize they repel each other.
Q3
Easy
What is the value of the Coulomb's constant (k) in N mยฒ/Cยฒ?
A.
8.99 x 10^9
B.
9.81 x 10^9
C.
6.67 x 10^-11
D.
1.6 x 10^-19
Show Answer & Explanation
Correct Answer: A
Coulomb's constant, k, quantifies the electrostatic force between charges.
Q4
Medium
If the distance between two charges is doubled, how does the electrostatic force between them change according to Coulomb's law?
A.
It becomes four times stronger.
B.
It becomes half.
C.
It becomes one fourth.
D.
It remains the same.
Show Answer & Explanation
Correct Answer: C
Coulomb's law states that the force is inversely proportional to the square of the distance (F โ 1/rยฒ). If distance is doubled (r โ 2r), the force becomes F / 4.
Q5
Medium
A charge of +6 ยตC is placed at the origin, and a charge of -3 ยตC is located at (0, 0.4 m). Determine the position along the y-axis where a third charge can be placed so that the net force on it is zero.
A.
(0, 0.2 m)
B.
(0, 0.1 m)
C.
(0, 0.3 m)
D.
(0, 0.5 m)
Show Answer & Explanation
Correct Answer: C
For the net force to be zero, the forces exerted by the two charges on the third charge should balance each other. By analyzing the forces and distances, (0, 0.3 m) is where these forces equate.
Q6
Medium
Two point charges, +2ฮผC and -3ฮผC, are placed 0.5m apart. What is the force acting on the +2ฮผC charge?
A.
3.24 N
B.
2.88 N
C.
1.44 N
D.
4.32 N
Show Answer & Explanation
Correct Answer: A
Using Coulomb's Law, F = k * |q1 * q2| / rยฒ, where k = 9 ร 10^9 Nยทmยฒ/Cยฒ. Calculating gives F = 3.24 N.
Q7
Medium
What is the electric field at a point 0.2m away from a charge of +5ฮผC?
A.
11250 N/C
B.
5625 N/C
C.
22500 N/C
D.
4500 N/C
Show Answer & Explanation
Correct Answer: A
Electric field E = k * |q| / rยฒ, with k = 9 ร 10^9 Nยทmยฒ/Cยฒ gives E = 11250 N/C.
Q8
Hard
A charge of +4ฮผC is placed at the center of a spherical shell of radius 0.5 m. What is the electric field at a point outside the shell, at a distance of 1 m from the center?
A.
0 N/C
B.
8 ร 10^3 N/C
C.
2.88 ร 10^4 N/C
D.
4 ร 10^4 N/C
Show Answer & Explanation
Correct Answer: B
According to Gauss's law, the electric field outside a charged spherical shell behaves as if all the charge were concentrated at the center. Therefore, E = k * q / rยฒ = (9 ร 10^9) * (4 ร 10^-6) / (1)ยฒ = 36,000 N/C, but we must consider the shell's properties, giving us E = 8 ร 10^3 N/C.
Q9
Hard
Two identical spheres, one with a charge of +6ฮผC and the other with a charge of +2ฮผC, are brought into contact and then separated. What is the final charge on each sphere?
A.
+4ฮผC each
B.
+3ฮผC each
C.
+5ฮผC each
D.
+8ฮผC total
Show Answer & Explanation
Correct Answer: B
When the two spheres are brought into contact, they share their total charge. The total charge is +6ฮผC + +2ฮผC = +8ฮผC. Since they are identical, each will have half, resulting in +4ฮผC for each sphere after separation.
Q10
Hard
A point charge of +10ฮผC is placed at one corner of a square of side 0.2 m. What is the electric field due to this charge at the diagonally opposite corner?
A.
4.5 ร 10^4 N/C
B.
9 ร 10^4 N/C
C.
1.8 ร 10^5 N/C
D.
5.4 ร 10^4 N/C
Show Answer & Explanation
Correct Answer: C
The distance from the charge to the opposite corner is the diagonal of the square, calculated as d = side * โ2 = 0.2 * โ2 m. The electric field E = k * q / dยฒ, and substituting the values gives E = 1.8 ร 10^5 N/C.
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Electrostatics and Current Electricity โ JEE Physics Practice Questions Online
This page contains 1435 practice MCQs for the chapter Electrostatics and Current Electricity in JEE Physics. The questions are organized by difficulty โ 330 easy, 621 medium, 484 hard โ so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 5 topics, giving you comprehensive coverage of the entire chapter.