Kinetic Theory of Gases Practice Questions

JEE · Physics · 1508 free MCQs with instant results and detailed explanations.

1508
Total
349
Easy
629
Medium
530
Hard

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Topics in Kinetic Theory of Gases

Degrees of Freedom 254
Mean Free Path 266
Ideal Gas Equation 258
Maxwell Distribution 281
Specific Heat Capacities 217
KTG Assumptions 232

Sample Questions from Kinetic Theory of Gases

Here are 10 sample questions. Start a quiz to get randomized questions with scoring.

Q1
Easy
What is the ideal gas equation?
A. PV = nRT
B. PV = mRT
C. PV = kT
D. PV = nR
Show Answer & Explanation
Correct Answer: A
The ideal gas equation relates pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T).
Q2
Easy
If the volume of an ideal gas is halved while keeping the temperature constant, what happens to the pressure?
A. It halves
B. It doubles
C. It stays the same
D. It quadruples
Show Answer & Explanation
Correct Answer: B
According to Boyle's Law, pressure is inversely proportional to volume at constant temperature. Halving the volume doubles the pressure.
Q3
Easy
How does the kinetic energy of an ideal gas relate to its temperature?
A. KE is inversely proportional to T
B. KE is directly proportional to T
C. KE is independent of T
D. KE is equal to 2T
Show Answer & Explanation
Correct Answer: B
The average kinetic energy of gas molecules is directly proportional to the temperature in Kelvin.
Q4
Medium
An ideal gas occupies a volume of 10 L at a pressure of 2 atm. If the temperature is doubled while keeping the volume constant, what will be the new pressure?
A. 4 atm
B. 2 atm
C. 1 atm
D. 3 atm
Show Answer & Explanation
Correct Answer: A
According to Gay-Lussac's law, pressure is directly proportional to temperature at constant volume. If the temperature is doubled, the pressure will also double.
Q5
Medium
If one mole of an ideal gas at 273 K occupies a volume of 22.4 L, what is the pressure of the gas in atm?
A. 1 atm
B. 0.5 atm
C. 2 atm
D. 3 atm
Show Answer & Explanation
Correct Answer: A
At STP, one mole of an ideal gas occupies 22.4 L at a pressure of 1 atm. Hence, the pressure of the gas is 1 atm.
Q6
Medium
A gas has a molar mass of 32 g/mol and is at a temperature of 300 K. Calculate its root mean square speed.
A. 200 m/s
B. 250 m/s
C. 300 m/s
D. 350 m/s
Show Answer & Explanation
Correct Answer: B
The root mean square speed (v_rms) can be calculated using the formula v_rms = sqrt(3RT/M). Using R = 8.314 J/(molยทK), we get v_rms = 250 m/s.
Q7
Medium
Consider two identical containers, one filled with an ideal gas at 300 K and the other at 600 K. Which gas has greater average kinetic energy?
A. Both have the same
B. Container at 600 K
C. Container at 300 K
D. Not enough information
Show Answer & Explanation
Correct Answer: B
The average kinetic energy of gas molecules is directly proportional to the absolute temperature. Therefore, the gas at 600 K has greater average kinetic energy.
Q8
Hard
A gas occupies a volume of 10 L at a pressure of 2 atm. What will be the new volume if the pressure is decreased to 1 atm at constant temperature?
A. 20 L
B. 10 L
C. 5 L
D. 15 L
Show Answer & Explanation
Correct Answer: A
According to Boyle's Law, pressure and volume are inversely related if the temperature is constant. Thus, P1V1 = P2V2.
Q9
Hard
What is the root mean square speed of nitrogen gas (N2) at a temperature of 300 K? (Molar mass of N2 = 28 g/mol)
A. 300 m/s
B. 430 m/s
C. 500 m/s
D. 200 m/s
Show Answer & Explanation
Correct Answer: B
The root mean square speed (v_rms) is given by v_rms = sqrt(3RT/M). We convert molar mass to kg for calculation.
Q10
Hard
In an experiment, 2 moles of an ideal gas are compressed isothermally from 20 L to 10 L. What is the work done on the gas? (R = 8.314 J/molยทK, T = 300 K)
A. 415.7 J
B. 829.4 J
C. 207.85 J
D. 623.0 J
Show Answer & Explanation
Correct Answer: A
The work done during isothermal compression is given by W = -nRT ln(Vf/Vi).

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Kinetic Theory of Gases โ€” JEE Physics Practice Questions Online

This page contains 1508 practice MCQs for the chapter Kinetic Theory of Gases in JEE Physics. The questions are organized by difficulty โ€” 349 easy, 629 medium, 530 hard โ€” so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 6 topics, giving you comprehensive coverage of the entire chapter.