Oscillations Practice Questions
JEE · Physics · 1585 free MCQs with instant results and detailed explanations.
1585
Total
368
Easy
683
Medium
534
Hard
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Topics in Oscillations
Spring-Mass System
249
Forced Oscillations and Resonance
298
Energy in SHM
244
Damped Oscillations
289
Simple Pendulum
266
Simple Harmonic Motion
239
Sample Questions from Oscillations
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
A body executing simple harmonic motion has a maximum displacement of 5 cm. What is its amplitude?
A.
0 cm
B.
2.5 cm
C.
5 cm
D.
10 cm
Show Answer & Explanation
Correct Answer: C
The amplitude of simple harmonic motion is defined as the maximum displacement from the mean position, which is 5 cm.
Q2
Easy
In a simple harmonic oscillator, if the displacement is halved, what happens to the restoring force?
A.
Halves
B.
Remains the same
C.
Doubles
D.
Increases by four times
Show Answer & Explanation
Correct Answer: A
The restoring force in SHM is directly proportional to the displacement. Halving the displacement halves the force.
Q3
Easy
If a simple harmonic oscillator has a frequency of 1 Hz, what is its angular frequency?
A.
2π rad/s
B.
1 rad/s
C.
4π rad/s
D.
0.5 rad/s
Show Answer & Explanation
Correct Answer: A
Angular frequency ω is related to frequency f by the equation ω = 2πf. For f = 1 Hz, ω = 2π rad/s.
Q4
Medium
A simple harmonic oscillator (SHO) has a total energy of 50 J and an amplitude of 0.1 m. What is the maximum speed of the oscillator?
A.
10 m/s
B.
5 m/s
C.
8 m/s
D.
2 m/s
Show Answer & Explanation
Correct Answer: B
The maximum speed in SHO is given by \(v_{max} = \omega A\), and total energy is \(E = \frac{1}{2} k A^2\). We find \(k = \frac{2E}{A^2} = 1000 N/m\) and \(\omega = \sqrt{\frac{k}{m}}\). Finally, we compute \(v_{max} = \sqrt{\frac{2E}{m}}\).
Q5
Medium
A mass-spring system oscillates with a frequency of 2 Hz. What is the angular frequency of the oscillation?
A.
2π rad/s
B.
4π rad/s
C.
1 rad/s
D.
π rad/s
Show Answer & Explanation
Correct Answer: A
Angular frequency is related to the frequency by the formula \(\omega = 2\pi f\). Thus, substituting f = 2 Hz gives \(\omega = 2 * \pi * 2 = 4\pi\) rad/s.
Q6
Medium
A pendulum exhibits simple harmonic motion. If its period is 3 seconds, what is its frequency?
A.
0.33 Hz
B.
1 Hz
C.
0.5 Hz
D.
1.5 Hz
Show Answer & Explanation
Correct Answer: A
Frequency is the reciprocal of the period. Therefore, frequency \(f = \frac{1}{T} = \frac{1}{3} \approx 0.33 Hz\).
Q7
Medium
A block oscillates on a frictionless surface with an amplitude of 0.15 m. If the maximum acceleration is 12 m/s², what is the angular frequency of the motion?
A.
20 rad/s
B.
30 rad/s
C.
40 rad/s
D.
10 rad/s
Show Answer & Explanation
Correct Answer: A
Maximum acceleration in SHM is given by \(a_{max} = \omega^2 A\). Thus, rearranging gives \(\omega = \sqrt{\frac{a_{max}}{A}}\). Substituting the values yields \(\omega = \sqrt{\frac{12}{0.15}} \approx 20 rad/s\).
Q8
Hard
A pendulum swings with a period of 2 seconds. If the length of the pendulum is increased to make the period 4 seconds, what is the new length?
A.
1 m
B.
4 m
C.
16 m
D.
9 m
Show Answer & Explanation
Correct Answer: C
The period T of a pendulum is given by T = 2π√(L/g). If T is doubled, L becomes 4 times, so L = (2^2) * (g/π^2) for the new period.
Q9
Hard
Two masses are connected by a spring and oscillate in simple harmonic motion. If one mass is twice the mass of the other, how does the frequency of the system compare to a single mass on a spring?
A.
The frequency is the same as a single mass.
B.
The frequency is twice that of a single mass.
C.
The frequency is half that of a single mass.
D.
The frequency cannot be determined.
Show Answer & Explanation
Correct Answer: C
The frequency of a mass-spring system is given by f = (1/2π)√(k/m). With two different masses, the reduced mass formula shows the effective mass is half, reducing the frequency.
Q10
Hard
In a simple harmonic oscillator, if the total mechanical energy is 200 J and the amplitude is 0.5 m, what is the mass of the oscillator?
A.
1 kg
B.
2 kg
C.
4 kg
D.
8 kg
Show Answer & Explanation
Correct Answer: C
Total energy in SHM is given by E = (1/2)kA². Rearranging gives k = (2E/A²). From k = mg/L, equate to find m = 4 kg.
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Oscillations — JEE Physics Practice Questions Online
This page contains 1585 practice MCQs for the chapter Oscillations in JEE Physics. The questions are organized by difficulty — 368 easy, 683 medium, 534 hard — so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 6 topics, giving you comprehensive coverage of the entire chapter.