Force Motion and Energy Practice Questions
K-12 (Philippines) · K-12 Science · 144 free MCQs with instant results and detailed explanations.
144
Total
51
Easy
74
Medium
19
Hard
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Sample Questions from Force Motion and Energy
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Q1
Easy
What is the primary force acting on an object that is falling freely towards the Earth?
A.
Gravity
B.
Friction
C.
Magnetism
D.
Tension
Show Answer & Explanation
Correct Answer: A
Gravity is the force that attracts a body towards the center of the Earth. It acts on any object in free fall, pulling it downward.
Q2
Easy
Which of the following is an example of potential energy?
A.
A moving car
B.
A stretched rubber band
C.
A flowing river
D.
A spinning top
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Correct Answer: B
Potential energy is the energy stored in an object due to its position or state. A stretched rubber band stores energy due to its tension, making it a clear example of potential energy.
Q3
Easy
What is the force that opposes the motion of an object in contact with a surface?
A.
Gravity
B.
Friction
C.
Magnetism
D.
Inertia
Show Answer & Explanation
Correct Answer: B
Friction is the force that resists the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. It opposes the motion of objects in contact with surfaces.
Q4
Medium
A 5 kg object is pushed with a force of 20 N. What is the acceleration of the object?
A.
2 m/sĀ²
B.
4 m/sĀ²
C.
5 m/sĀ²
D.
8 m/sĀ²
Show Answer & Explanation
Correct Answer: B
According to Newton's second law, F = ma. Here, F = 20 N and m = 5 kg. Thus, a = F/m = 20 N / 5 kg = 4 m/sĀ², making option B the correct answer.
Q5
Medium
Which of the following statements correctly describes potential energy?
A.
It is the energy of motion.
B.
It is energy stored due to an object's position.
C.
It is energy transferred during collisions.
D.
It is energy produced by chemical reactions.
Show Answer & Explanation
Correct Answer: B
Potential energy is defined as the energy stored in an object due to its position or configuration. It increases with height and is not related to motion, which makes option B correct.
Q6
Medium
If a car travels 150 meters in 5 seconds, what is its average speed?
A.
25 m/s
B.
30 m/s
C.
35 m/s
D.
40 m/s
Show Answer & Explanation
Correct Answer: B
Average speed is computed by dividing the total distance traveled by the total time taken. Hence, speed = distance/time = 150 m / 5 s = 30 m/s, which confirms option B.
Q7
Medium
Which type of energy is associated with the movement of particles in an object?
A.
Kinetic energy
B.
Potential energy
C.
Mechanical energy
D.
Nuclear energy
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Correct Answer: A
Kinetic energy is defined as the energy that an object possesses due to its motion, which includes the movement of its particles. Therefore, option A is correct.
Q8
Hard
A car accelerates uniformly from rest to a speed of 20 m/s in 5 seconds. What is the total distance covered by the car during this time?
A.
50 meters
B.
100 meters
C.
200 meters
D.
25 meters
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Correct Answer: A
Using the formula for distance covered under uniform acceleration, d = ut + (1/2)at^2, where u = initial velocity (0 m/s), t = time (5 s), and a = final velocity/t = 20 m/s / 5 s = 4 m/s^2, we find d = 0 + (1/2)(4)(5^2) = 50 meters.
Q9
Hard
Two objects, A and B, collide elastically. Object A has a mass of 4 kg and is moving at 6 m/s, while object B has a mass of 6 kg and is initially at rest. What will be the final velocity of object A after the collision?
A.
2 m/s
B.
4 m/s
C.
6 m/s
D.
0 m/s
Show Answer & Explanation
Correct Answer: B
In an elastic collision, both momentum and kinetic energy are conserved. Using conservation of momentum: m1u1 + m2u2 = m1v1 + m2v2, we can set up the equations. Let v1 be the final velocity of A and v2 be the final velocity of B. Solving the equations for A's final velocity yields 4 m/s.
Q10
Hard
A 10 kg cart is pushed with a force of 50 N. If the frictional force opposing the motion is 10 N, what is the acceleration of the cart?
A.
4 m/sĀ²
B.
5 m/sĀ²
C.
3 m/sĀ²
D.
6 m/sĀ²
Show Answer & Explanation
Correct Answer: A
To find the acceleration, we first calculate the net force acting on the cart, which is the applied force minus the frictional force (50 N - 10 N = 40 N). Using Newton's second law (F = ma), we can find acceleration by rearranging the equation to a = F/m. Thus, a = 40 N / 10 kg = 4 m/sĀ².
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Force Motion and Energy ā K-12 (Philippines) K-12 Science Practice Questions Online
This page contains 144 practice MCQs for the chapter Force Motion and Energy in K-12 (Philippines) K-12 Science. The questions are organized by difficulty ā 51 easy, 74 medium, 19 hard ā so you can choose the right level for your preparation.
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