Pressure Practice Questions
KCSE (Kenya) · KCSE Physics · 147 free MCQs with instant results and detailed explanations.
147
Total
45
Easy
77
Medium
25
Hard
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Sample Questions from Pressure
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
If the height of a column of mercury in a barometer is 760 mm, what is the pressure exerted by the column in pascals?
A.
7600 Pa
B.
760000 Pa
C.
76000 Pa
D.
760 Pa
Show Answer & Explanation
Correct Answer: B
The pressure exerted by a column of mercury can be calculated using the formula P = hρg, where h is the height in meters, ρ is the density of mercury (approximately 13546 kg/m³), and g is the acceleration due to gravity (approximately 9.81 m/s²). Here, P = 0.76 m * 13546 kg/m³ * 9.81 m/s² = 760000 Pa.
Q2
Easy
What is the formula for calculating pressure?
A.
Pressure = Force / Area
B.
Pressure = Area / Force
C.
Pressure = Force x Area
D.
Pressure = Force + Area
Show Answer & Explanation
Correct Answer: A
The formula for pressure is defined as the force exerted per unit area, which is Pressure = Force / Area. This relationship shows how much force is applied over a specific area.
Q3
Easy
A diver is at a depth of 30 m in the ocean. If the density of seawater is approximately 1030 kg/m³, what is the pressure due to the water above him? (Consider gravity as 9.8 m/s²)
A.
2940 Pa
B.
29400 Pa
C.
294000 Pa
D.
2940000 Pa
Show Answer & Explanation
Correct Answer: C
The pressure at a depth can be calculated using the formula Pressure = density × gravity × height. Here, Pressure = 1030 kg/m³ × 9.8 m/s² × 30 m = 294000 Pa.
Q4
Medium
A cylindrical container with a radius of 0.5 m is filled with water to a height of 2 m. What is the pressure exerted by the water at the bottom of the container? (Assume density of water = 1000 kg/m³ and g = 10 m/s²)
A.
10,000 Pa
B.
20,000 Pa
C.
30,000 Pa
D.
40,000 Pa
Show Answer & Explanation
Correct Answer: B
The pressure at the bottom is given by P = ρgh. Here, ρ = 1000 kg/m³, g = 10 m/s², and h = 2 m. Therefore, P = 1000 * 10 * 2 = 20,000 Pa.
Q5
Medium
A scuba diver is at a depth of 30 m in the ocean. Calculate the total pressure on the diver, taking atmospheric pressure to be 101,325 Pa. (Density of seawater = 1025 kg/m³, g = 9.81 m/s²)
A.
303,225 Pa
B.
307,325 Pa
C.
311,225 Pa
D.
315,225 Pa
Show Answer & Explanation
Correct Answer: B
Total pressure is given by P_total = P_atm + ρgh. Here, P_atm = 101,325 Pa, ρ = 1025 kg/m³, g = 9.81 m/s², and h = 30 m. Thus, P_total = 101,325 + 1025 * 9.81 * 30 = 307,325 Pa.
Q6
Medium
Why does a sharp knife cut better than a blunt knife when applying the same force?
A.
It has a larger surface area.
B.
It creates a lower pressure.
C.
It has a smaller surface area.
D.
It requires less force to cut.
Show Answer & Explanation
Correct Answer: C
A sharp knife has a smaller surface area, which increases the pressure applied on the material being cut. Higher pressure leads to better cutting efficiency.
Q7
Medium
A hydraulic press has an input piston of area 0.01 m² and an output piston of area 0.5 m². If a force of 100 N is applied to the input piston, what is the force exerted by the output piston?
A.
200 N
B.
500 N
C.
1000 N
D.
2500 N
Show Answer & Explanation
Correct Answer: C
Using Pascal's principle, the pressure is the same in both pistons. Pressure at input = Force/Input Area = 100 N / 0.01 m² = 10,000 Pa. The force at the output can be calculated as Output Pressure = Input Pressure, hence Output Force = Pressure * Output Area = 10,000 Pa * 0.5 m² = 1000 N.
Q8
Hard
A column of mercury is 76 cm high. Calculate the pressure exerted at the base of the column in pascals. (Density of mercury = 13,600 kg/m³; g = 9.81 m/s²)
A.
1.01 × 10⁵ Pa
B.
9.81 × 10⁴ Pa
C.
1.03 × 10⁵ Pa
D.
1.05 × 10⁵ Pa
Show Answer & Explanation
Correct Answer: A
Using the formula for pressure, P = hρg, where h is height, ρ is density, and g is acceleration due to gravity, we find P = 0.76 m * 13600 kg/m³ * 9.81 m/s² = 1.01 × 10⁵ Pa.
Q9
Hard
A scuba diver is at a depth of 30 meters in the ocean. If the atmospheric pressure at the surface is 101325 Pa, what is the total pressure experienced by the diver (assuming the density of seawater is approximately 1025 kg/m³)?
A.
301325 Pa
B.
301425 Pa
C.
303325 Pa
D.
305325 Pa
Show Answer & Explanation
Correct Answer: A
The total pressure experienced by the diver is the sum of atmospheric pressure and the hydrostatic pressure due to the column of seawater above. Hydrostatic pressure can be calculated using P = ρgh. Therefore, the total pressure is P_total = P_atmospheric + ρgh = 101325 Pa + (1025 kg/m³ * 9.81 m/s² * 30 m) = 301325 Pa.
Q10
Hard
A cylindrical container with a height of 2 m and a radius of 0.5 m is filled with water. If the density of water is 1000 kg/m³, what is the pressure at the bottom of the container due to the water column? (Use g = 9.81 m/s²)
A.
9800 Pa
B.
19620 Pa
C.
4905 Pa
D.
24510 Pa
Show Answer & Explanation
Correct Answer: B
The pressure at the bottom of the container is calculated using the formula P = hρg, where h is the height (2 m), ρ is the density (1000 kg/m³), and g is the acceleration due to gravity (9.81 m/s²). Thus, P = 2 * 1000 * 9.81 = 19620 Pa.
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Pressure — KCSE (Kenya) KCSE Physics Practice Questions Online
This page contains 147 practice MCQs for the chapter Pressure in KCSE (Kenya) KCSE Physics. The questions are organized by difficulty — 45 easy, 77 medium, 25 hard — so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.