Motion Practice Questions
NECO (Nigeria) · NECO Physics · 140 free MCQs with instant results and detailed explanations.
140
Total
54
Easy
68
Medium
18
Hard
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Sample Questions from Motion
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Q1
Easy
Which of the following statements correctly describes uniform motion?
A.
The object moves with changing speed.
B.
The object moves with constant speed in a straight line.
C.
The object is at rest.
D.
The object moves in a circular path.
Show Answer & Explanation
Correct Answer: B
Uniform motion refers to motion in a straight line with constant speed, meaning the object covers equal distances in equal intervals of time.
Q2
Easy
An object is thrown upward with an initial velocity of 20 m/s. Ignoring air resistance, what will be its velocity at the highest point?
A.
20 m/s
B.
0 m/s
C.
-20 m/s
D.
10 m/s
Show Answer & Explanation
Correct Answer: B
At the highest point of its trajectory, the velocity of the object becomes zero before it starts to descend due to gravity.
Q3
Easy
A car accelerates from rest to a speed of 25 m/s in 10 seconds. What is its acceleration?
A.
2.5 m/s²
B.
5 m/s²
C.
10 m/s²
D.
7.5 m/s²
Show Answer & Explanation
Correct Answer: A
Acceleration is defined as the change in velocity over time. Here, acceleration = (final velocity - initial velocity) / time = (25 m/s - 0 m/s) / 10 s = 2.5 m/s².
Q4
Medium
A car accelerates uniformly from rest and reaches a speed of 30 m/s in 10 seconds. What is the acceleration of the car?
A.
3 m/s²
B.
1.5 m/s²
C.
2 m/s²
D.
5 m/s²
Show Answer & Explanation
Correct Answer: A
Acceleration is calculated using the formula a = (v - u) / t. Here, initial velocity (u) = 0, final velocity (v) = 30 m/s, and time (t) = 10 s. Thus, a = (30 - 0) / 10 = 3 m/s².
Q5
Medium
An object is thrown vertically upward with a velocity of 20 m/s. How high will it rise before coming to a momentary stop? (Assume g = 10 m/s²)
A.
20 m
B.
30 m
C.
40 m
D.
10 m
Show Answer & Explanation
Correct Answer: A
Using the formula h = (v² - u²) / (2g), where u = 20 m/s, v = 0 m/s at the highest point, and g = 10 m/s², we find h = (0 - (20)²) / (2 * -10) = 20 m.
Q6
Medium
Two cars are moving in the same direction. Car A has a speed of 90 km/h and Car B has a speed of 60 km/h. What is the relative speed of Car A with respect to Car B?
A.
30 km/h
B.
150 km/h
C.
90 km/h
D.
60 km/h
Show Answer & Explanation
Correct Answer: A
Relative speed is the difference in speeds when objects are moving in the same direction. Therefore, relative speed = Speed of A - Speed of B = 90 km/h - 60 km/h = 30 km/h.
Q7
Medium
A cyclist is moving with an initial velocity of 5 m/s and accelerates at a rate of 2 m/s² for 8 seconds. What is the final velocity of the cyclist?
A.
21 m/s
B.
14 m/s
C.
10 m/s
D.
16 m/s
Show Answer & Explanation
Correct Answer: A
Final velocity can be calculated using the formula v = u + at, where u = 5 m/s, a = 2 m/s², and t = 8 s. Thus, v = 5 + (2)(8) = 5 + 16 = 21 m/s.
Q8
Hard
A car accelerates uniformly from rest to a speed of 25 m/s in 10 seconds. Calculate the distance covered by the car during this time.
A.
125 m
B.
250 m
C.
100 m
D.
50 m
Show Answer & Explanation
Correct Answer: A
The distance covered during uniformly accelerated motion can be calculated using the formula: distance = initial speed × time + (1/2) × acceleration × time². Since the car starts from rest, the initial speed is 0. The acceleration can be found using the formula: acceleration = (final speed - initial speed) / time = (25 m/s - 0) / 10 s = 2.5 m/s². Therefore, distance = 0 × 10 + 0.5 × 2.5 × (10)² = 125 m.
Q9
Hard
A car accelerates uniformly from rest to a speed of 25 m/s over a distance of 200 m. What is the acceleration of the car?
A.
1.56 m/s²
B.
3.12 m/s²
C.
6.25 m/s²
D.
12.5 m/s²
Show Answer & Explanation
Correct Answer: A
Using the formula v² = u² + 2as, where u = 0 (initial velocity), v = 25 m/s (final velocity), and s = 200 m (distance), we can solve for acceleration (a). Rearranging gives us a = (v² - u²) / (2s) = (25² - 0²) / (2 * 200) = 1.56 m/s².
Q10
Hard
An object is thrown vertically upwards with a speed of 20 m/s. Calculate the time taken to reach its highest point. (Assume acceleration due to gravity g = 10 m/s²)
A.
2 seconds
B.
4 seconds
C.
1 second
D.
3 seconds
Show Answer & Explanation
Correct Answer: A
The time taken to reach the highest point is calculated using the formula t = v/g, where v is the initial velocity and g is the acceleration due to gravity. Here, t = 20 m/s ÷ 10 m/s² = 2 seconds.
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Motion — NECO (Nigeria) NECO Physics Practice Questions Online
This page contains 140 practice MCQs for the chapter Motion in NECO (Nigeria) NECO Physics. The questions are organized by difficulty — 54 easy, 68 medium, 18 hard — so you can choose the right level for your preparation.
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