Some Basic Concepts of Chemistry Practice Questions

NEET · Chemistry · 1491 free MCQs with instant results and detailed explanations.

1491

Total

355

Easy

652

Medium

484

Hard

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Topics in Some Basic Concepts of Chemistry

Equivalent Concept 305

Stoichiometry 254

Mole Concept 274

Concentration Terms 278

Atomic and Molecular Mass 380

Sample Questions from Some Basic Concepts of Chemistry

Here are 10 sample questions. Start a quiz to get randomized questions with scoring.

Easy

What is the mole fraction of a solute if 2 moles of solute are dissolved in 3 moles of solvent?

A. 0.4

B. 0.6

C. 0.5

D. 0.2

Show Answer & Explanation

Correct Answer: A

Mole fraction of solute = moles of solute / (moles of solute + moles of solvent) = 2 / (2 + 3) = 0.4.

Easy

How many grams are in 0.5 moles of water (H₂O)? (Molar mass of H₂O = 18 g/mol)

A. 9 g

B. 18 g

C. 36 g

D. 27 g

Show Answer & Explanation

Correct Answer: A

Mass = moles × molar mass = 0.5 × 18 = 9 grams.

Easy

How many particles are in 2 moles of sodium chloride (NaCl)? (Avogadro's number = 6.022 x 10²³)

A. 1.2044 x 10²⁴

B. 6.022 x 10²³

C. 1.2044 x 10²³

D. 2 x 6.022 x 10²³

Show Answer & Explanation

Correct Answer: A

Number of particles = moles × Avogadro's number = 2 × 6.022 x 10²³ = 1.2044 x 10²⁴.

Medium

What is the mass of 1 mole of water (H₂O)?

A. 18 g

B. 36 g

C. 12 g

D. 24 g

Show Answer & Explanation

Correct Answer: A

The molar mass of water is calculated as follows: H has a molar mass of approximately 1 g/mol and O has a molar mass of approximately 16 g/mol. Therefore, the total mass of 1 mole of water (H₂O) is (2 × 1) + 16 = 18 g.

Medium

If 3 moles of a gas occupy 60 liters at STP, what is the molar volume of the gas?

A. 20 L

B. 30 L

C. 40 L

D. 60 L

Show Answer & Explanation

Correct Answer: A

At STP, 1 mole of an ideal gas occupies 22.4 liters. Therefore, for 3 moles: Volume = 3 moles × 22.4 L/mole = 67.2 L. Since the question states it occupies 60 L, we find that the molar volume is 60 L / 3 moles = 20 L.

Medium

How many moles are present in 88 g of carbon dioxide (CO₂)?

A. 2 moles

B. 1 mole

C. 4 moles

D. 3 moles

Show Answer & Explanation

Correct Answer: A

The molar mass of CO₂ is calculated as follows: C (12 g/mol) + O (16 g/mol × 2) = 44 g/mol. To find moles: Moles = mass (g) / molar mass (g/mol) = 88 g / 44 g/mol = 2 moles.

Medium

A solution contains 0.5 moles of NaCl in 1 liter. What is the concentration of the solution in mol/L?

A. 0.25 M

B. 0.5 M

C. 1 M

D. 0.75 M

Show Answer & Explanation

Correct Answer: B

Concentration is calculated as moles of solute per liter of solution. Here, concentration = 0.5 moles / 1 L = 0.5 M (molarity).

Hard

How many molecules are present in 0.2 moles of water?

A. 1.204 x 10^23

B. 3.01 x 10^23

C. 1.6 x 10^23

D. 6.02 x 10^23

Show Answer & Explanation

Correct Answer: A

Using Avogadro's number (6.02 x 10^23 molecules/mole), the number of molecules in 0.2 moles is 0.2 * 6.02 x 10^23 = 1.204 x 10^23.

Hard

What is the molarity of a solution containing 58.5 grams of NaCl in 1 liter of solution?

A. 0.5 M

B. 1 M

C. 2 M

D. 0.25 M

Show Answer & Explanation

Correct Answer: B

The molar mass of NaCl is 58.5 g/mol. Hence, the number of moles = 58.5 g / 58.5 g/mol = 1 mole, which gives a molarity of 1 M when dissolved in 1 liter.

Q10

Hard

If 2 moles of a compound has a mass of 342 grams, what is the molar mass of the compound?

A. 171 g/mol

B. 342 g/mol

C. 684 g/mol

D. 85.5 g/mol

Show Answer & Explanation

Correct Answer: A

Molar mass is calculated by dividing the total mass by the number of moles. Here, molar mass = 342 g / 2 moles = 171 g/mol.

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Some Basic Concepts of Chemistry — NEET Chemistry Practice Questions Online

This page contains 1491 practice MCQs for the chapter Some Basic Concepts of Chemistry in NEET Chemistry. The questions are organized by difficulty — 355 easy, 652 medium, 484 hard — so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 5 topics, giving you comprehensive coverage of the entire chapter.