Kinetic Theory of Gases Practice Questions
NEET · Physics · 1496 free MCQs with instant results and detailed explanations.
1496
Total
340
Easy
664
Medium
492
Hard
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Topics in Kinetic Theory of Gases
Degrees of Freedom
367
Law of Equipartition
370
Kinetic Theory
390
Ideal Gas Equation
369
Sample Questions from Kinetic Theory of Gases
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
What is the ideal gas equation represented as?
A.
PV = nRT
B.
PV = nRT^2
C.
PV = nR
D.
PV = nT
Show Answer & Explanation
Correct Answer: A
The ideal gas equation is stated as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.
Q2
Easy
If the volume of an ideal gas is doubled while maintaining a constant temperature, what happens to the pressure?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Show Answer & Explanation
Correct Answer: C
According to Boyle's Law, at constant temperature, if the volume of a gas increases, the pressure decreases inversely. Therefore, if volume is doubled, the pressure halves.
Q3
Easy
Which of the following is a characteristic of an ideal gas?
A.
Has no volume
B.
Particles have elastic collisions
C.
Intermolecular forces are strong
D.
Cannot expand
Show Answer & Explanation
Correct Answer: B
An ideal gas is characterized by having particles that collide elastically, meaning no kinetic energy is lost in collisions. Options A and C do not describe ideal gas behavior.
Q4
Medium
What is the value of the universal gas constant R in terms of LยทkPa/Kยทmol?
A.
8.314
B.
0.0821
C.
62.36
D.
1.987
Show Answer & Explanation
Correct Answer: B
The value of R is 0.0821 LยทkPa/Kยทmol, which is used when pressure is in kilopascals and volume is in liters.
Q5
Medium
An ideal gas occupies a volume of 3.0 L at a pressure of 2.0 atm. What will be its volume if the pressure is increased to 4.0 atm at constant temperature?
A.
1.5 L
B.
3.0 L
C.
6.0 L
D.
2.0 L
Show Answer & Explanation
Correct Answer: A
According to Boyle's Law, P1V1 = P2V2. Therefore, (2.0 atm)(3.0 L) = (4.0 atm)(V2), giving V2 = 1.5 L.
Q6
Medium
What is the relationship between the total kinetic energy of an ideal gas and its temperature?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
Show Answer & Explanation
Correct Answer: A
The total kinetic energy of an ideal gas is directly proportional to its absolute temperature (KE = (3/2)nRT).
Q7
Medium
If the density of an ideal gas is increased while keeping temperature constant, what happens to its pressure?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
Show Answer & Explanation
Correct Answer: A
According to the ideal gas equation PV = nRT, if density increases and temperature is constant, pressure must increase as well.
Q8
Hard
A gas is compressed isothermally from a volume of 10 L to 5 L, while maintaining a temperature of 300 K. If the initial pressure of the gas is 1 atm, what is the final pressure?
A.
2 atm
B.
0.5 atm
C.
1 atm
D.
3 atm
Show Answer & Explanation
Correct Answer: A
According to Boyle's Law, for an isothermal process, P1V1 = P2V2. Here, P1 = 1 atm, V1 = 10 L, V2 = 5 L. Therefore, P2 = (P1 * V1) / V2 = (1 * 10)/5 = 2 atm.
Q9
Hard
A sample of an ideal gas occupies a volume of 50 L at a pressure of 2 atm and a temperature of 300 K. If the gas is heated at constant pressure until its volume doubles, what will be the new temperature of the gas?
A.
600 K
B.
300 K
C.
150 K
D.
350 K
Show Answer & Explanation
Correct Answer: A
According to Charles's Law, V1/T1 = V2/T2 at constant pressure. Here, V1 = 50 L, T1 = 300 K and V2 = 100 L. Rearranging gives T2 = V2 * T1 / V1 = (100 * 300) / 50 = 600 K.
Q10
Hard
An ideal gas undergoes an adiabatic process, changing from an initial state of 1 atm and 300 K to a final volume of 0.5 L. What is the final temperature of the gas if its initial volume is 2 L?
A.
600 K
B.
300 K
C.
150 K
D.
450 K
Show Answer & Explanation
Correct Answer: A
For an adiabatic process, P1V1^ฮณ = P2V2^ฮณ and T1V1^(ฮณ-1) = T2V2^(ฮณ-1) where ฮณ (gamma) for a diatomic ideal gas is approximately 1.4. Using initial conditions and solving gives T2 = 600 K.
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Kinetic Theory of Gases โ NEET Physics Practice Questions Online
This page contains 1496 practice MCQs for the chapter Kinetic Theory of Gases in NEET Physics. The questions are organized by difficulty โ 340 easy, 664 medium, 492 hard โ so you can choose the right level for your preparation.
Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit. This chapter covers 4 topics, giving you comprehensive coverage of the entire chapter.