Forces and Motion Practice Questions
SPM (Malaysia) · SPM Physics · 135 free MCQs with instant results and detailed explanations.
135
Total
43
Easy
73
Medium
19
Hard
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Sample Questions from Forces and Motion
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Q1
Easy
Which of the following statements is true regarding an object in uniform motion?
A.
It has constant acceleration.
B.
It experiences no net force.
C.
It has constant velocity.
D.
It is at rest.
Show Answer & Explanation
Correct Answer: C
An object in uniform motion travels at a constant velocity, meaning its speed and direction remain unchanged over time.
Q2
Easy
What is the unit of force in the International System of Units (SI)?
A.
Newton
B.
Pound
C.
Joule
D.
Kilogram
Show Answer & Explanation
Correct Answer: A
The Newton (N) is the SI unit of force, defined as the force required to accelerate a one-kilogram mass by one meter per second squared.
Q3
Easy
Which force opposes the motion of an object sliding on a surface?
A.
Friction
B.
Gravity
C.
Normal Force
D.
Tension
Show Answer & Explanation
Correct Answer: A
Friction is the force that resists the sliding motion of two surfaces in contact, acting in the opposite direction of the object's movement.
Q4
Medium
A 10 kg block is resting on a horizontal surface. What is the normal force acting on the block?
A.
0 N
B.
10 N
C.
100 N
D.
50 N
Show Answer & Explanation
Correct Answer: C
The normal force equals the weight of the block. Weight (W) is calculated as W = mass × gravity, where gravity is approximately 10 m/s². Thus, W = 10 kg × 10 m/s² = 100 N.
Q5
Medium
An object is in equilibrium under the influence of three forces: 5 N to the right, 3 N to the left, and a third unknown force. What should the value and direction of the third force be to keep the object in equilibrium?
A.
2 N to the right
B.
2 N to the left
C.
3 N to the right
D.
No third force is needed
Show Answer & Explanation
Correct Answer: B
For the object to be in equilibrium, the net force must be zero. The forces to the right (5 N) and to the left (3 N) create a net force of 2 N to the right, thus a 2 N force to the left is needed to balance it.
Q6
Medium
A 10 kg block is pulled on a flat surface with a force of 50 N. If the frictional force acting on it is 20 N, what is the net force acting on the block?
A.
30 N
B.
50 N
C.
20 N
D.
10 N
Show Answer & Explanation
Correct Answer: A
Net force is calculated by subtracting the frictional force from the applied force: Net force = applied force - frictional force = 50 N - 20 N = 30 N, hence option A is correct.
Q7
Medium
A cyclist travels 40 meters north and then turns and travels 30 meters east. What is the resultant displacement of the cyclist from the starting point?
A.
50 m
B.
70 m
C.
10 m
D.
60 m
Show Answer & Explanation
Correct Answer: A
Using the Pythagorean theorem for the right triangle formed, the resultant displacement is calculated as √(40² + 30²) = √(1600 + 900) = √2500 = 50 m, making option A correct.
Q8
Hard
A car accelerates uniformly from rest to a speed of 25 m/s over a distance of 100 meters. What is the acceleration of the car?
A.
3.125 m/s²
B.
6.25 m/s²
C.
1.5 m/s²
D.
5.0 m/s²
Show Answer & Explanation
Correct Answer: A
Using the equation v² = u² + 2as, where v is final velocity (25 m/s), u is initial velocity (0 m/s), and s is the distance (100 m), we can calculate the acceleration a. 25² = 0 + 2a(100) gives a = 3.125 m/s².
Q9
Hard
A car accelerates uniformly from rest to a speed of 25 m/s in 10 seconds. What is the distance covered by the car during this time?
A.
125 m
B.
250 m
C.
50 m
D.
75 m
Show Answer & Explanation
Correct Answer: A
The distance covered during uniform acceleration can be calculated using the formula: distance = initial velocity × time + 0.5 × acceleration × time². Here, initial velocity is 0, acceleration can be calculated as (25 m/s) / (10 s) = 2.5 m/s². Substituting into the formula gives: distance = 0 × 10 + 0.5 × 2.5 × (10)² = 0 + 125 = 125 m.
Q10
Hard
A toy car is pushed along a frictionless surface with a force of 10 N. If the mass of the car is 2 kg, what is its acceleration?
A.
5 m/s²
B.
10 m/s²
C.
20 m/s²
D.
2 m/s²
Show Answer & Explanation
Correct Answer: A
According to Newton's second law, acceleration (a) is given by the formula F = ma, where F is the net force and m is the mass. Here, a = F/m = 10 N / 2 kg = 5 m/s².
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Forces and Motion — SPM (Malaysia) SPM Physics Practice Questions Online
This page contains 135 practice MCQs for the chapter Forces and Motion in SPM (Malaysia) SPM Physics. The questions are organized by difficulty — 43 easy, 73 medium, 19 hard — so you can choose the right level for your preparation.
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