Magnetism Practice Questions
Thanaweya Amma (Egypt) · Thanaweya Physics · 152 free MCQs with instant results and detailed explanations.
152
Total
49
Easy
76
Medium
27
Hard
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Sample Questions from Magnetism
Here are 10 sample questions. Start a quiz to get randomized questions with scoring.
Q1
Easy
If a current-carrying wire is placed in a magnetic field, what will happen?
A.
No effect will occur.
B.
The wire will experience a force.
C.
The wire will heat up immediately.
D.
The magnetic field will disappear.
Show Answer & Explanation
Correct Answer: B
A current-carrying wire in a magnetic field experiences a force due to the interaction between the magnetic field and the electric current. This is the principle behind electric motors.
Q2
Easy
What is the direction of the magnetic field around a straight current-carrying conductor?
A.
It is radial outwards.
B.
It is circular and perpendicular to the current.
C.
It is always in the direction of the current.
D.
It is parallel to the conductor.
Show Answer & Explanation
Correct Answer: B
The magnetic field around a straight current-carrying conductor forms concentric circles that are perpendicular to the direction of the current. This is described by the right-hand grip rule.
Q3
Easy
What happens to a compass needle when it is brought near a magnet?
A.
It aligns itself with the magnetic field.
B.
It does not react at all.
C.
It points in the opposite direction.
D.
It spins randomly.
Show Answer & Explanation
Correct Answer: A
A compass needle is a small magnet and will align itself with the magnetic field of any nearby magnet, showing the direction of the field lines.
Q4
Medium
A current-carrying conductor is placed in a magnetic field. What will be the direction of the force acting on the conductor?
A.
Perpendicular to both magnetic field and current direction
B.
In the same direction as the magnetic field
C.
In the opposite direction to the current
D.
Parallel to the current direction
Show Answer & Explanation
Correct Answer: A
According to Fleming's left-hand rule, the force on a current-carrying conductor in a magnetic field is always perpendicular to both the direction of the magnetic field and the current.
Q5
Medium
If the magnetic flux through a coil changes at a rate of 0.5 Wb/s, what is the induced electromotive force (emf) in the coil with 100 turns?
A.
50 V
B.
5 V
C.
0.5 V
D.
5.0 V
Show Answer & Explanation
Correct Answer: A
The induced emf can be calculated using Faraday's law of electromagnetic induction: emf = -N * (change in flux/change in time). Here, emf = -100 * 0.5 = -50 V (ignoring the negative sign as we are interested in magnitude).
Q6
Medium
A solenoid with 200 turns per meter carries a current of 3 A. What is the magnetic field strength inside the solenoid?
A.
1.2 T
B.
0.8 T
C.
0.6 T
D.
0.4 T
Show Answer & Explanation
Correct Answer: A
The magnetic field strength (B) inside a solenoid is given by the formula B = ฮผโ * n * I, where n is the number of turns per meter and I is the current. Here, B = (4ฯ ร 10โปโท T m/A) * 200/m * 3 A = 1.2 T.
Q7
Medium
A magnet is dropped from a height into a coil. What effect will this have on the coil?
A.
No effect
B.
Induces an emf and current
C.
Causes the coil to heat up instantly
D.
Reverses the magnetic field in the coil
Show Answer & Explanation
Correct Answer: B
When the magnet moves through the coil, it changes the magnetic flux through the coil, inducing an electromotive force (emf) and consequently an electric current according to Faraday's law of electromagnetic induction.
Q8
Hard
A circular loop of wire with a radius of 0.1 m carries a current of 5 A. What is the magnetic field strength at the center of the loop? (Use ฮผโ = 4ฯ ร 10โปโท Tm/A)
A.
1.57 ร 10โปโต T
B.
3.14 ร 10โปโต T
C.
7.85 ร 10โปโต T
D.
6.28 ร 10โปโต T
Show Answer & Explanation
Correct Answer: A
The magnetic field (B) at the center of a circular loop is given by the formula B = (ฮผโ * I) / (2 * R). Here, I = 5 A, R = 0.1 m, and ฮผโ = 4ฯ ร 10โปโท Tm/A. Plugging in these values results in B = (4ฯ ร 10โปโท * 5) / (2 * 0.1) = 1.57 ร 10โปโต T.
Q9
Hard
Two long parallel wires are 0.5 m apart and carry equal currents of 10 A in the same direction. What is the magnitude of the force per unit length between the wires? (Use ฮผโ = 4ฯ ร 10โปโท Tm/A)
A.
4 ร 10โปโถ N/m
B.
1 ร 10โปโถ N/m
C.
2 ร 10โปโถ N/m
D.
8 ร 10โปโถ N/m
Show Answer & Explanation
Correct Answer: A
The force per unit length (F/L) between two parallel wires is given by F/L = (ฮผโ * Iโ * Iโ) / (2ฯ * d). Here, Iโ = Iโ = 10 A and d = 0.5 m. Thus, F/L = (4ฯ ร 10โปโท * 10 * 10) / (2ฯ * 0.5) = 4 ร 10โปโถ N/m.
Q10
Hard
A circular loop of wire with a radius of 0.1 m carries a current of 5 A. Calculate the magnetic field strength at the center of the loop. (Use the formula B = (ฮผโ * I) / (2 * R), where ฮผโ = 4ฯ x 10โปโท Tยทm/A)
A.
3.14 x 10โปโถ T
B.
1.57 x 10โปโถ T
C.
6.28 x 10โปโถ T
D.
2.51 x 10โปโถ T
Show Answer & Explanation
Correct Answer: A
Using the formula B = (ฮผโ * I) / (2 * R), we substitute ฮผโ = 4ฯ x 10โปโท, I = 5 A, and R = 0.1 m. This results in B = (4ฯ x 10โปโท * 5) / (2 * 0.1) = 3.14 x 10โปโถ T, making option A correct.
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Magnetism โ Thanaweya Amma (Egypt) Thanaweya Physics Practice Questions Online
This page contains 152 practice MCQs for the chapter Magnetism in Thanaweya Amma (Egypt) Thanaweya Physics. The questions are organized by difficulty โ 49 easy, 76 medium, 27 hard โ so you can choose the right level for your preparation.
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