Dao động cơ Practice Questions

THPT (Vietnam) · THPT Vật lý · 145 free MCQs with instant results and detailed explanations.

145
Total
51
Easy
72
Medium
22
Hard

Start Practicing Dao động cơ

Take a timed quiz or customize your practice session

Quick Quiz (10 Qs) → Mock Test (25 Qs) ⚙ Customize

Sample Questions from Dao động cơ

Here are 10 sample questions. Start a quiz to get randomized questions with scoring.

Q1
Easy
In simple harmonic motion, if the displacement is halved, how does the restoring force change?
A. It doubles
B. It halves
C. It remains the same
D. It decreases by a factor of four
Show Answer & Explanation
Correct Answer: B
In simple harmonic motion, the restoring force (F) is directly proportional to displacement (x), according to Hooke's Law (F = -kx). Halving the displacement halves the restoring force.
Q2
Easy
A mass-spring system oscillates with a period of 2 seconds. What is the frequency of this oscillation?
A. 0.5 Hz
B. 2 Hz
C. 4 Hz
D. 1 Hz
Show Answer & Explanation
Correct Answer: A
Frequency is the reciprocal of the period. Therefore, frequency = 1/period = 1/2 seconds = 0.5 Hz.
Q3
Easy
What type of motion does a simple pendulum exhibit when displaced and then released?
A. Uniform motion
B. Rotational motion
C. Simple harmonic motion
D. Linear motion
Show Answer & Explanation
Correct Answer: C
A simple pendulum exhibits simple harmonic motion because it oscillates back and forth around its equilibrium position due to the restoring force of gravity.
Q4
Medium
If the amplitude of a harmonic oscillation is doubled, how does this affect the total energy of the system?
A. Energy remains the same
B. Energy is halved
C. Energy is doubled
D. Energy is quadrupled
Show Answer & Explanation
Correct Answer: D
The energy of a harmonic oscillator is proportional to the square of the amplitude. If the amplitude is doubled, the energy increases by a factor of 2^2 = 4.
Q5
Medium
A mass attached to a spring oscillates with a frequency of 4 Hz. What is the angular frequency of the mass-spring system?
A. 8π rad/s
B. 4π rad/s
C. 2π rad/s
D. 16π rad/s
Show Answer & Explanation
Correct Answer: B
Angular frequency (ω) is related to frequency (f) by the formula ω = 2πf. For a frequency of 4 Hz, ω = 2π * 4 = 8π rad/s.
Q6
Medium
What is the phase difference between two identical harmonic oscillators oscillating in opposite directions?
A. 0 degrees
B. 90 degrees
C. 180 degrees
D. 360 degrees
Show Answer & Explanation
Correct Answer: C
Harmonic oscillators oscillating in opposite directions have a phase difference of 180 degrees, which means they are completely out of sync.
Q7
Medium
A mass-spring system oscillates with a frequency of 2 Hz. What is the period of oscillation?
A. 0.5 seconds
B. 1 second
C. 2 seconds
D. 4 seconds
Show Answer & Explanation
Correct Answer: A
The period (T) is the reciprocal of the frequency (f). T = 1/f, so T = 1/2 = 0.5 seconds.
Q8
Hard
A mass-spring system oscillates with a frequency of 2 Hz. What is the period of the oscillation?
A. 0.5 seconds
B. 1 second
C. 2 seconds
D. 4 seconds
Show Answer & Explanation
Correct Answer: A
The period (T) is the reciprocal of the frequency (f). Here, T = 1/f = 1/2 = 0.5 seconds. This is correct as it reflects the relationship between period and frequency.
Q9
Hard
A mass-spring system oscillates with an amplitude of 0.1 m. If the spring constant is 400 N/m, what is the maximum speed of the mass during its oscillation?
A. 2 m/s
B. 0.5 m/s
C. 1 m/s
D. 4 m/s
Show Answer & Explanation
Correct Answer: A
The maximum speed (v_max) in simple harmonic motion can be calculated using the formula v_max = ωA, where ω is the angular frequency given by ω = √(k/m). Here, we can rearrange the formula to find v_max directly as v_max = A√(k/m). Assuming m = 1 kg for simplicity, we calculate ω = √(400/1) = 20 rad/s. Thus, v_max = 0.1 * 20 = 2 m/s.
Q10
Hard
A pendulum with a length of 1 m swings with small angles. If the pendulum completes 20 oscillations in 40 seconds, what is the period of the pendulum?
A. 1.0 s
B. 2.0 s
C. 0.5 s
D. 1.5 s
Show Answer & Explanation
Correct Answer: B
The period (T) of a pendulum is defined as the time taken for one complete oscillation. Given that the pendulum completes 20 oscillations in 40 seconds, we can calculate the period as T = total time / number of oscillations = 40 s / 20 = 2 s. Thus, the correct answer is 2.0 seconds.

Showing 10 of 145 questions. Start a quiz to practice all questions with scoring and timer.

Practice All 145 Questions →

Dao động cơ — THPT (Vietnam) THPT Vật lý Practice Questions Online

This page contains 145 practice MCQs for the chapter Dao động cơ in THPT (Vietnam) THPT Vật lý. The questions are organized by difficulty — 51 easy, 72 medium, 22 hard — so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.