Fisika Modern Practice Questions
UN (Indonesia) · UN Fisika · 151 free MCQs with instant results and detailed explanations.
151
Total
53
Easy
74
Medium
24
Hard
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Sample Questions from Fisika Modern
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Q1
Easy
What is the primary principle behind the photoelectric effect?
A.
Light can be treated as both a wave and a particle.
B.
Electrons are emitted from a metal surface when exposed to heat.
C.
The frequency of light has no effect on electron emission.
D.
Only UV light can cause the emission of electrons from any metal.
Show Answer & Explanation
Correct Answer: A
The photoelectric effect demonstrates that light exhibits both wave-like and particle-like properties, which is crucial in understanding quantum mechanics.
Q2
Easy
If a particle has a mass of 2 kg and is moving with a velocity of 3 m/s, what is its kinetic energy?
A.
3 Joules
B.
9 Joules
C.
6 Joules
D.
18 Joules
Show Answer & Explanation
Correct Answer: B
The kinetic energy (KE) is calculated using the formula KE = 0.5 * m * vยฒ. For this particle, KE = 0.5 * 2 kg * (3 m/s)ยฒ = 9 Joules.
Q3
Easy
In a nuclear reaction, what is emitted when a neutron is released from a nucleus?
A.
An electron
B.
A proton
C.
A gamma ray
D.
No emission occurs
Show Answer & Explanation
Correct Answer: D
When a neutron is emitted from a nucleus, it does not lead to the emission of any charged particle or radiation; thus, 'no emission occurs' is correct.
Q4
Medium
What is the principle behind the photoelectric effect?
A.
Light can be absorbed by electrons and cause them to be emitted.
B.
Light can change the temperature of an object.
C.
Light can only be reflected and not absorbed.
D.
Light travels faster in a vacuum than in water.
Show Answer & Explanation
Correct Answer: A
The photoelectric effect demonstrates that light can transfer energy to electrons, allowing them to escape from a material when sufficient energy is provided.
Q5
Medium
If a proton and an electron are placed in an electric field, which particle will experience a greater force?
A.
Proton
B.
Electron
C.
They experience the same force.
D.
Neither will experience any force.
Show Answer & Explanation
Correct Answer: C
Both the proton and electron experience the same force in an electric field since force is calculated as F = qE, and the charge of the proton is equal in magnitude but opposite in sign to that of the electron.
Q6
Medium
A 2 kg block slides down a frictionless incline of 30 degrees. What is its acceleration?
A.
4.9 m/sยฒ
B.
9.8 m/sยฒ
C.
5.0 m/sยฒ
D.
3.0 m/sยฒ
Show Answer & Explanation
Correct Answer: A
The acceleration of the block can be found using the formula a = g * sin(ฮธ). Here, g = 9.8 m/sยฒ and ฮธ = 30 degrees, thus a = 9.8 * 0.5 = 4.9 m/sยฒ.
Q7
Medium
In which type of reaction is energy released as a result of nuclear fission?
A.
Exothermic reaction
B.
Endothermic reaction
C.
Isothermal reaction
D.
Adiabatic reaction
Show Answer & Explanation
Correct Answer: A
Nuclear fission is classified as an exothermic reaction because it releases energy when the nucleus of an atom splits into smaller parts.
Q8
Hard
A photon has a wavelength of 500 nm. What is its energy in joules?
A.
3.97 x 10^-19 J
B.
6.63 x 10^-19 J
C.
3.24 x 10^-19 J
D.
5.00 x 10^-19 J
Show Answer & Explanation
Correct Answer: A
The energy of a photon is calculated using the formula E = hc/ฮป. Here, h = 6.63 x 10^-34 Jยทs, c = 3 x 10^8 m/s, and ฮป = 500 nm = 500 x 10^-9 m. Plugging in these values gives E = (6.63 x 10^-34 Jยทs)(3 x 10^8 m/s) / (500 x 10^-9 m) = 3.97 x 10^-19 J.
Q9
Hard
A nucleus undergoes alpha decay and emits an alpha particle. If the original nucleus has a mass of 238 u, what is the mass of the remaining nucleus after decay?
A.
234 u
B.
236 u
C.
238 u
D.
240 u
Show Answer & Explanation
Correct Answer: A
During alpha decay, the nucleus emits an alpha particle (which consists of 2 protons and 2 neutrons). Thus, when a nucleus of mass 238 u emits an alpha particle (mass approximately 4 u), the remaining nucleus will have a mass of 238 u - 4 u = 234 u.
Q10
Hard
A particle is moving in a potential well described by V(x) = kx^2/2, where k is a constant. If the particle's total energy is E, what is the maximum displacement of the particle from the equilibrium position?
A.
โ(2E/k)
B.
E/k
C.
2E/k
D.
k/E
Show Answer & Explanation
Correct Answer: A
The maximum displacement occurs when the kinetic energy is zero, and all energy is potential: E = V(x) = kx^2/2. Solving for x gives x_max = โ(2E/k).
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Fisika Modern โ UN (Indonesia) UN Fisika Practice Questions Online
This page contains 151 practice MCQs for the chapter Fisika Modern in UN (Indonesia) UN Fisika. The questions are organized by difficulty โ 53 easy, 74 medium, 24 hard โ so you can choose the right level for your preparation.
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