Listrik dan Magnet Practice Questions

UN (Indonesia) · UN Fisika · 137 free MCQs with instant results and detailed explanations.

137
Total
36
Easy
76
Medium
25
Hard

Start Practicing Listrik dan Magnet

Take a timed quiz or customize your practice session

Quick Quiz (10 Qs) → Mock Test (25 Qs) ⚙ Customize

Sample Questions from Listrik dan Magnet

Here are 10 sample questions. Start a quiz to get randomized questions with scoring.

Q1
Easy
What is the unit of electric current in the International System of Units (SI)?
A. Volt
B. Ampere
C. Ohm
D. Coulomb
Show Answer & Explanation
Correct Answer: B
The unit of electric current is the Ampere, which measures the flow of electric charge. It is defined as one coulomb per second.
Q2
Easy
If a circuit has a resistance of 5 Ohms and a voltage of 10 Volts, what is the current flowing through the circuit?
A. 2 Amperes
B. 5 Amperes
C. 10 Amperes
D. 50 Amperes
Show Answer & Explanation
Correct Answer: A
Using Ohm's law (V = IR), where V is voltage, I is current, and R is resistance, we rearrange to find I = V/R. Thus, I = 10V / 5ฮฉ = 2A.
Q3
Easy
A magnet has a north and a south pole. What will happen if you cut the magnet in half?
A. It will create a new south pole only.
B. It will create two smaller magnets, each with a north and south pole.
C. The poles will disappear.
D. It will create only one magnet with two poles.
Show Answer & Explanation
Correct Answer: B
When a magnet is cut in half, each half becomes a smaller magnet with its own north and south pole due to the alignment of magnetic domains within.
Q4
Medium
What is the effect of doubling the voltage in a circuit while maintaining the same resistance?
A. The current will double.
B. The current will remain the same.
C. The current will halve.
D. The resistance will double.
Show Answer & Explanation
Correct Answer: A
According to Ohm's Law (V = IR), if the voltage (V) is doubled and resistance (R) remains constant, the current (I) must also double.
Q5
Medium
A wire carrying a current of 5 A is placed in a magnetic field of strength 0.2 T. What is the force experienced by the wire if its length in the magnetic field is 2 m and the angle between the wire and the magnetic field is 90 degrees?
A. 1 N
B. 2 N
C. 5 N
D. 10 N
Show Answer & Explanation
Correct Answer: B
The formula for the force on a current-carrying wire is F = BIL sin(ฮธ). Here, B = 0.2 T, I = 5 A, L = 2 m, and ฮธ = 90 degrees (sin(90) = 1). Thus, F = 0.2 * 5 * 2 * 1 = 2 N.
Q6
Medium
When two resistors of 4 ฮฉ and 6 ฮฉ are connected in series, what is the total resistance?
A. 2 ฮฉ
B. 4 ฮฉ
C. 10 ฮฉ
D. 24 ฮฉ
Show Answer & Explanation
Correct Answer: C
In a series connection, the total resistance R is the sum of individual resistances: R_total = R1 + R2 = 4 ฮฉ + 6 ฮฉ = 10 ฮฉ.
Q7
Medium
A capacitor of capacitance 10 ยตF is charged to a voltage of 12 V. What is the energy stored in the capacitor?
A. 0.6 mJ
B. 0.72 mJ
C. 1.2 mJ
D. 1.44 mJ
Show Answer & Explanation
Correct Answer: B
The energy (E) stored in a capacitor is given by the formula E = 1/2 CVยฒ. Substituting C = 10 ยตF (10 x 10^-6 F) and V = 12 V, E = 1/2 * 10 x 10^-6 * (12)ยฒ = 0.72 mJ.
Q8
Hard
Two parallel plates are charged to a potential difference of 500 V and separated by a distance of 0.01 m. What is the magnitude of the electric field between the plates?
A. 25,000 N/C
B. 50,000 N/C
C. 75,000 N/C
D. 100,000 N/C
Show Answer & Explanation
Correct Answer: B
The electric field E between two charged plates is given by E = V/d, where V is the potential difference and d is the distance between the plates. Substituting the given values, E = 500 V / 0.01 m = 50,000 N/C.
Q9
Hard
A long straight wire carries a current of 10 A. Calculate the magnetic field strength at a point 0.05 m away from the wire. (Use ฮผโ‚€ = 4ฯ€ ร— 10^-7 Tยทm/A)
A. 4ฯ€ ร— 10^-6 T
B. 2 ร— 10^-5 T
C. 1.6 ร— 10^-5 T
D. 8 ร— 10^-6 T
Show Answer & Explanation
Correct Answer: B
The magnetic field (B) around a long straight conductor is given by the formula B = (ฮผโ‚€ * I) / (2 * ฯ€ * r). Substituting the values: B = (4ฯ€ ร— 10^-7 Tยทm/A * 10 A) / (2 * ฯ€ * 0.05 m) = 2 ร— 10^-5 T.
Q10
Hard
Two parallel wires carrying currents in the same direction are separated by a distance of 0.1 m. If the current in both wires is 5 A, what is the force per unit length acting between the wires? (Use ฮผโ‚€ = 4ฯ€ ร— 10^-7 Tยทm/A)
A. 1 ร— 10^-5 N/m
B. 2 ร— 10^-5 N/m
C. 1.25 ร— 10^-5 N/m
D. 3 ร— 10^-5 N/m
Show Answer & Explanation
Correct Answer: A
The force per unit length (F/L) between two parallel wires carrying current is given by F/L = (ฮผโ‚€ * Iโ‚ * Iโ‚‚) / (2 * ฯ€ * d). For Iโ‚ = Iโ‚‚ = 5 A and d = 0.1 m, F/L = (4ฯ€ ร— 10^-7 * 5 * 5) / (2 * ฯ€ * 0.1) = 1 ร— 10^-5 N/m.

Showing 10 of 137 questions. Start a quiz to practice all questions with scoring and timer.

Practice All 137 Questions →

Listrik dan Magnet โ€” UN (Indonesia) UN Fisika Practice Questions Online

This page contains 137 practice MCQs for the chapter Listrik dan Magnet in UN (Indonesia) UN Fisika. The questions are organized by difficulty โ€” 36 easy, 76 medium, 25 hard โ€” so you can choose the right level for your preparation.

Every question includes a detailed explanation to help you understand the concept, not just memorize answers. Take a timed quiz to simulate exam conditions, or practice at your own pace with no time limit.